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Fudgin [204]
3 years ago
7

2. The three sub-atomic particles that make up the atom are

Chemistry
1 answer:
AlladinOne [14]3 years ago
5 0

Answer:

Protons

Neutrons

Electrons

Explanation:

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Júpiter and 60000 the are the awnsers

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Fresh water freezes faster
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Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the
mojhsa [17]

Answer:

Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the

temperature of the water. The water in the beaker began to boil when it reached the temperature of

100'C. If Mario completes the same experiment with 25mL of water, what would happen to the boiling

point?

a) The water will not reach a boil.

b) The boiling point of water will increase.

c) The boiling point of water will decrease.

d) The boiling point of water will stay the same.

Explanation:

6 0
3 years ago
A slurry of flakes soybeans weighing a total of 100 kg contains 75 kg of inert solids and 25 kg of solution with 10 wt% oil and
lubasha [3.4K]

Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

C= solvent(oil)

F_{solution} = mass of solvent + mass of oil (i.e A+C)

<u>Feed Phase:</u>

Total feed (i.e slurry of flakes soybeans)= 100kg

B= mass of solid =75 kg

F= mass of solvent + mass of oil (i.e A+C)

 = 25kg

Mass ratio of oil to solution Y_{F} =\frac{Mass C}{Mass (A+C)}

mass of oil (C) =25 × 0.1 wt = 2.5kg

mass of hexane  in feed = 25 ×  0.9 =22.5kg + 2.5 =25kg

therefore  Y_{F} = \frac{2.5}{25}

= 0.1

mass ratio of solid to solution Y_{A}  =  \frac{Mass A}{Mass (A+C)}=[tex]\frac{75}{25}

=3

<u>Solvent Phase:</u>

C= Mass of oil= 0(kg)

A= Mass of hexane = 100kg

mass of solutions = A+C = 0+100kg

solvent= 100kg

<u>Underflow:</u>

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

the value of N for the outlet and underflow is 1.5 kg

i.e N₁ = \frac{mass B}{mass(A+C)}

solution in underflow E₁ = Mass (A+C)

<u>Overflow:</u>

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75=  E₁ × N₁

75 =  E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

5 0
3 years ago
Water is being pumped from the bottom of a well 150 feet deep at a rate of 200 gal/hour into a vented storage tank 30 feet above
KengaRu [80]

Explanation:

As the given data is as follows.

        Height, H = 150 feet

 Heat gain = 30,000 BTU/hr,  and  Heat loss = 25000 BTU/hr

  m = mass of water heated = 700 gallons = 5810 lbs

C_{p} is the heat capacity of water = 1 BTU/lb ^{o}F (given)

      \Delta T = temperature difference = 120^{o}F - 35^{o}F

Heat energy required to heat 700 gal can be calculated as follows:

    Heat Required = 5810 lbs \times 1 BTU/lb^{o}F \times (120^{o}F - 35^{o}F)

Thus, water rises till 120^{o}F.

3 0
3 years ago
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