INFORMATION:
Is given that:
- if you have a block of plastic and a block of copper that are the same mass and are placed in the sun for 10 minutes.
And after the 10 minutes copper has a higher temperature.
We must determine the reason.
STEP BY STEP EXPLANATION:
To determine it, we need to know the concept of specific heat
If the block of copper has a higher temperature after 10 minutes, that means copper needs less heat to raise its temperature.
So, plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly.
ANSWER:
The explanation for the copper having a higher temperature after 10 minutes in the sun, is that plastic has a higher specific heat than metal, so it takes more energy to heat plastic than copper. As a result, plastic would heat up more slowly. Since the copper has a lower specific heat, it will be heat quickly.
Answer:
84 g of N₂
Explanation:
We begin from the reaction:
N₂O₄ + 2N₂H₄ → 3N₂ + 4H₂O
1st step: Find out the limiting reactant.
We convert the mass to moles.
276 g . 1mol/ 92g = 3 moles of N₂O₄
64 g . 1mol / 32g = 2 moles of hidrazine
Limiting reactant is the hydrazine. Ratio is 1:2, then for 3 moles of tetroixde I may need 6 moles of N₂H₄. (But I only have 2).
To determine the grams of produced nitrogen we see stoichiometry (2:3)
2 moles of hydrazine can produce 3 moles of N₂
Definetaly our 2 moles make 3 moles of gas.
We convert the moles to mass.
3 mol . 28g /1mol = 84 g of N₂
Answer:
Explanation:
a) 4-nitrobenzoic acid pKa= 3.41
benzoic acid pKa= 4.19
4-chlorobenzoic acid pKa= 3.98
b) benzoic acid pKa= 4.19
cyclohexanol pKa= 18.0
phenol pKa= 9.95
c) 4-Nitrobenzoic acid pKa= 3.41
4-nitrophenol pKa= 7.15
4-nitrophenylacetic acid pKa= 3.85
Answer:
13.5 %
Explanation:
First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:
- 500 mL * 1.00 g/mL = 500 g
Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:
Mass of Potassium Sulfate / Total Mass * 100%
- 78 g / (78 + 500) g * 100 % = 13.5 %
Answer:
![M_{HCl} = 1.12M](https://tex.z-dn.net/?f=M_%7BHCl%7D%20%3D%201.12M)
Explanation:
Hello!
In this case, for the first reaction we need to focus on, the neutralization of magnesium hydroxide by phosphoric acid, we can write up the following equation:
![3Mg(OH)_2+2H_3PO_4\rightarrow Mg_3(PO_4)_2+6H_2O](https://tex.z-dn.net/?f=3Mg%28OH%29_2%2B2H_3PO_4%5Crightarrow%20Mg_3%28PO_4%29_2%2B6H_2O)
Whereas the acid and base react in a 3:2 mole ratio; thus, we can write:
![2M_{Mg(OH)_2}V_{Mg(OH)_2}=3M_{H_3PO_4}V_{H_3PO_4}](https://tex.z-dn.net/?f=2M_%7BMg%28OH%29_2%7DV_%7BMg%28OH%29_2%7D%3D3M_%7BH_3PO_4%7DV_%7BH_3PO_4%7D)
Now, solving for the concentration of the magnesium hydroxide solution we get:
![M_{Mg(OH)_2}=\frac{3M_{H_3PO_4}V_{H_3PO_4}}{2V_{Mg(OH)_2}} \\\\M_{Mg(OH)_2}=\frac{3*0.20M*0.0300L}{2*0.050L}=0.18M](https://tex.z-dn.net/?f=M_%7BMg%28OH%29_2%7D%3D%5Cfrac%7B3M_%7BH_3PO_4%7DV_%7BH_3PO_4%7D%7D%7B2V_%7BMg%28OH%29_2%7D%7D%20%5C%5C%5C%5CM_%7BMg%28OH%29_2%7D%3D%5Cfrac%7B3%2A0.20M%2A0.0300L%7D%7B2%2A0.050L%7D%3D0.18M)
Now, for the reaction between hydrochloric acid and magnesium hydroxide we have:
![Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O](https://tex.z-dn.net/?f=Mg%28OH%29_2%2B2HCl%5Crightarrow%20MgCl_2%2B2H_2O)
![2M_{Mg(OH)_2}V_{Mg(OH)_2}=M_{HCl}V_{HCl}](https://tex.z-dn.net/?f=2M_%7BMg%28OH%29_2%7DV_%7BMg%28OH%29_2%7D%3DM_%7BHCl%7DV_%7BHCl%7D)
Therefore, solving for the concentration of the hydrochloric acid solution we get:
![M_{HCl}=\frac{2M_{Mg(OH)_2}V_{Mg(OH)_2}}{V_{HCl}} \\\\M_{HCl}=\frac{2*0.18M*0.078L}{0.025L}\\\\M_{HCl} = 1.12M](https://tex.z-dn.net/?f=M_%7BHCl%7D%3D%5Cfrac%7B2M_%7BMg%28OH%29_2%7DV_%7BMg%28OH%29_2%7D%7D%7BV_%7BHCl%7D%7D%20%5C%5C%5C%5CM_%7BHCl%7D%3D%5Cfrac%7B2%2A0.18M%2A0.078L%7D%7B0.025L%7D%5C%5C%5C%5CM_%7BHCl%7D%20%3D%201.12M)
Best regards!