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garik1379 [7]
3 years ago
10

We'll need a new what to support the cleaner energy world of the future.

Chemistry
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

Renewable source of energy

Using unrenewable sources is destroying the earth

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Epsom salt, a common hydrate, has the formula shown below. If I measure out 125 g of epsom salt to add to my foot soak, what mas
tatiyna

Answer:

The answer to your question is 64.02 g of H₂O

Explanation:

Data

Mass of magnesium sulfate hepta hydrated = 125 g

Mass of water = ?

Process

1.- Calculate the molar mass of the salt and the molar mass of water

molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g

mass of H₂O = 2 + 16 = 18 g

2.- Use proportions to calculate the mass of water in the epsom salt

                246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O

                125 g                        -------------------------   x

                x = (125 x 126)/246

                x = 15750/246

               x = 64.02 g of H₂O

6 0
3 years ago
IM JUST GIVING AWAY POINTS!!!!!!
myrzilka [38]
2.5128e10 is the answer
6 0
3 years ago
Read 2 more answers
11.<br> The electron configuration for phosphorous is [Ar]3s23p4.<br> TRUE<br> FALSE
user100 [1]

Answer:

False

Explanation:

Phosphorus is number 15 on the periodic table, so its electronic configuration is:

{1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{3}

5 0
2 years ago
How Mendeleev's systematic approach resulted in the development of his Periodic Table of elements.
tensa zangetsu [6.8K]
I just wanna know what does that even mean
6 0
3 years ago
When aqueous solutions of manganese(II) iodide and sodium phosphate are combined, solid manganese(II) phosphate and a solution o
Feliz [49]

Answer:

The net ionic equation for the given reaction :

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

Explanation:

3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)...[1]

MnI_2(aq)\rightarrow Mn^{2+}(aq)+2I^-(aq)..[2]

Na_3PO_4(aq)\rightarrow 3Na^{+}(aq)+PO_4^{3-}(aq)...[3]

NaI(aq)\rightarrow Na^+(aq)+I^-(aq)

Replacing MnI_2(aq) , NaI and Na_3PO_4(aq) in [1] by usig [2] [3] and [4]

3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

8 0
3 years ago
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