1 kg =1000 g = 10³ g,
1 m = 100 cm ,
(1m)³ = (100 cm)³= (10²)³ cm³ = 10⁶ cm³ or 10⁶ mL
5,427 kg/m³ = <span>5,427 kg/ 1m³ = (5427 * 10³ g)/ 10⁶ mL=5427/10³ g/mL=
=5427/1000 g/mL = 5.427 g/mL
</span>5.427 g/mL is density of Mercury, and 1.0 g/mL is density of water.
Density of Mercury is more then density of the water, so
mercury will sink in the water.
The maximum number is 10 electrons
Answer: D) 1 lone pair, square pyramidal
Explanation:
Formula used : ![\text{Number of electrons}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom = 7
N = number of monovalent atoms bonded to central atom = 5
C = charge of cation = 0
A = charge of anion = 0
Now we have to determine the hybridization of the
molecule.
![\text{Number of electrons}=\frac{1}{2}\times [7+5+0-0]=6](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B7%2B5%2B0-0%5D%3D6)
Bond pair electrons = 5
Lone pair electrons = 6-5 = 1
The number of electrons are 6 that means the hybridization will be
and the electronic geometry of the molecule will be octahedral .
But as there are five atoms around the central iodine atom, the sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square pyramidal.
I pick but I'm not sure about it though 1and3
Answer:
it woul be 263
Explanation:
becaue it adds up like that