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Tju [1.3M]
3 years ago
6

Changing the position of the increases or decreases your effort

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
Changing what position?
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When an object transfers energy to another object, does it always transfer all of it’s energy?
valentinak56 [21]

Answer:

Conservation of energy means that the total change of energy in any system is always equal to the total energy transferred into or out of the system.

3 0
3 years ago
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When doing a recrystallization what observations would prompt you to perform a hot filtration?
KATRIN_1 [288]
Answer is: <span>because dissolved compounds can crystallizing from solution during filtration and forming crystals on the filter paper or funnel.
</span>Recrystallization<span> is a technique used to purify chemicals by dissolving both impurities and a compound in an appropriate solvent, either compound or impurities can be removed from the solution, leaving the other behind.</span>
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La masse et volume. S'il vous plaît repondre aux questions 2, 3, et 4.​
ella [17]

Answer:

Bonjour! Je me demandais si vous pouviez s’il vous plaît traduire vos questions en anglais afin que je puisse les résoudre. J’utilise un traducteur en ce moment pour vous dire votre réponse dans Français. Je suis désolé si vous ne pouvez pas traduire cela. Bonne journée!

Explanation:

3 0
3 years ago
If the molar heat of combustion of liquid benzene at constant volume and 300k is -3272KJ. Calculate the heat of combustion at co
vladimir2022 [97]

Answer:

The heat at constant pressure is -3,275.7413 kJ

Explanation:

The combustion equation is 2C₆H₆ (l) + 15O₂ (g)  → 12CO₂ (g) + 6H₂O (l)

\Delta n_g = (12 - 15)/2 = -3/2

We have;

\Delta H = \Delta U + \Delta n_g\cdot R\cdot T

Where R and T are constant, and ΔU is given we can write the relationship as follows;

H = U + \Delta n_g\cdot R\cdot T

Where;

H = The heat at constant pressure

U = The heat at constant volume = -3,272 kJ

\Delta n_g = The change in the number of gas molecules per mole

R = The universal gas constant = 8.314 J/(mol·K)

T = The temperature = 300 K

Therefore, we get;

H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ

The heat at constant pressure, H = -3,275.7413 kJ.

4 0
2 years ago
How many Molecules are in 20 grams of CO?
Mademuasel [1]

Answer:

2.74 x 1023 molecules of CO2.

Explanation:

There are 2.74 x 1023 molecules of CO2.

7 0
2 years ago
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