If the channel-Length modulation effect is neglected, ID in the saturation region is considered to be independent of VDS

What are some ways you can design a working future notebook that writes for you when you speak

irina [24]

Answer:

maybe use a text-to speech type of software and implement it into a printer

4 0

3 years ago

A 250-pound person would use a Type 1 ladder even if he were carrying a load with him. true or false

serg [7]

Answer:

The answer is False.

Explanation:

Type 1 ladders have a duty rating of 250-pounds. The fact that the person is carrying a load means that they are exceeding 250 pounds.

Type 1A would be best.

In other words, it's better to be safe than sorry.

Source: Ladder Safety PDF

-Lexi

8 0

3 years ago

Which number of pounds of grapes and total cost of the grapes could be used as the missing values in the table

Allisa [31]

Answer:

The price of 2 pounds of grapes i.e. $1.38 and the price of 8 pounds of grapes i.e. $5.52 are the missing values on the table.

Step-by-step explanation:

The number of pounds and the total cost of grapes in dollars are given in the table.

From the table the price of grapes can be calculated as dollars per pound.

Now, 2 pounds of grapes costs $(0.69 × 2) = $1.38

And, 3 pounds of grapes costs $(0.69 × 3) = $2.07

And, 6 pounds of grapes costs $(0.69 × 6) = $4.14

And, 8 pounds of grapes costs $(0.69 × 8) = $5.52

And, 11 pounds of grapes costs $(0.69 × 11) = $7.59

Therefore, the price of 2 pounds of grapes i.e. $1.38 and the price of 8 pounds of grapes i.e. $5.52 are the missing values on the table.

Explanation:

i think its right

6 0

2 years ago

You are evaluating the lifetime of a turbine blade. The blade is 4 cm long and there is a gap of 0.16 cm between the tip of the

Tcecarenko [31]

Answer:

Explanation:

Given conditions

1)The stress on the blade is 100 MPa

2)The yield strength of the blade is 175 MPa

3)The Young’s modulus for the blade is 50 GPa

4)The strain contributed by the primary creep regime (not including the initial elastic strain) was 0.25 % or 0.0025 strain, and this strain was realized in the first 4 hours.

5)The temperature of the blade is 800°C.

6)The formula for the creep rate in the steady-state regime is dε /dt = 1 x 10-5 σ4 exp (-2 eV/kT)

where: dε /dt is in cm/cm-hr σ is in MPa T is in Kelvink = 8.62 x 10-5 eV/K

Young Modulus, E = Stress, $\sigma$ /Strain, ∈

initial Strain, $\epsilon_i = \frac{\sigma}{E}$

$\epsilon_i = \frac{100\times 10^{6} Pa}{50\times 10^{9} Pa}$

$\epsilon_i = 0.002$

creep rate in the steady state

$\frac{\delta \epsilon}{\delta t} = (1 \times {10}^{-5})\sigma^4 exp^(\frac{-2eV}{kT} )$

$\frac{\epsilon_{initial} - \epsilon _{primary}}{t_{initial}-t_{final}} = 1 \times 10^{-5}(100)^{4}exp(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )(800+273)K} )$

but Tinitial = 0

$\epsilon_{initial} - \epsilon _{primary}} = 0.002 - 0.003 = -0.001$

$\frac{-0.001}{-t_{final}} = 1 \times 10^{-5}(100)^{4}\times 10^{(\frac{-2eV}{8.62\times10^{-5}(\frac{eV}{K} )1073K} )}$

solving the above equation,

we get

Tfinal = 2459.82 hr

3 0

3 years ago

A power screw is 30 mm in diameter and has a thread pitch of 5 mm. Find the thread depth, the thread width, the mean and root di

ankoles [38]

Answer:

thread depth = 2.5 mm

thread width = 2.5 mm

mean diameter = 27.5 mm

root diameter = 25 mm

lead of screw = 5 mm

Explanation:

given data

power screw diameter D = 30 mm

thread pitch P = 5 mm

solution

First, we get here thread depth fr square thread

thread depth = $\frac{P}{2}$ ......................1

thread depth = $\frac{5}{2}$

thread depth = 2.5 mm

and

thread width for square thread

thread width = $\frac{P}{2}$ ......................2

thread width = $\frac{5}{2}$

thread width = 2.5 mm

and

mean diameter is

mean diameter = D - $\frac{P}{2}$ ................3

mean diameter = 30 - $\frac{5}{2}$

mean diameter = 27.5 mm

and

root diameter is

root diameter = D - P ....................4

root diameter = 30 - 5

root diameter = 25 mm

and

lead of screw for single thread so n = 1

so lead of screw = 1 × 5

lead of screw = 5 mm

4 0

3 years ago