The height at which the mass will be lifted is; 3 meters
<h3>How to utilize efficiency of a machine?</h3>
Formula for efficiency is;
η = useful output energy/input energy
We are given
η = 60% = 0.6
Input energy = 4 KJ = 4000 J
Thus;
0.6 = useful output energy/4000
useful output energy = 0.6 * 4000
useful output energy = 2400 J
Work done in lifting mass(useful output energy) = force * distance moved
Useful output energy = 800 * h
where h is height to lift mass
Thus;
800h = 2400
h = 2400/800
h = 3 meters
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Answer:
Cost = $2527.2 per month.
Explanation:
Given that
Discharge ,Q = 130 L/min
So
Cost = $0.45 per cubic meter
1 month = 30 days
1 days = 24 hr = 24 x 60 min
1 month = 30 x 24 x 60 min
1 month = 43,200 min
Lets x
x = 0.13 x 43,200
So the total cost = 5616 x 045 $
Cost = $2527.2 per month.
Answer:
Δ enthalpy = -23 Btu/Ibm
Explanation:
Given data:
Pressure ( P1 ) = 250 psi
Initial Temperature ( T1 ) = 175°F
Final temperature ( T2 ) = 20°F
<u>Calculate the change in the enthalpy of R-134a </u>
From R-134 table
h1 = 129.85 Btu/Ibm
s1 = 0.23281 Btu/Ibm.R
note : entropy is constant
hence ; s1 = s2
by interpolation ; h2 = 106.95
Δ enthalpy = h2 - h1
= ( 106.95 - 129.85 ) = -23 Btu/Ibm
