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2 years ago

Mount Everest is approximately 8,000 meters high. How many miles high is Mount Everest?

2 answers:

4 0

Although its precise height is disputed, Everest rises to some 29,108 feet (8872 meters), or about 5.5 miles high, the tallest in the greatest chain of mountains on earth, the Himalayas." "Exact Mt. Everest Measurement Made." Hope it helps

strojnjashka [21]2 years ago

3 0

Answer:

Mount Everest is 4.97 miles high

Explanation:

we know,

1 meter = 0.0006213712 mile

so,

8000 meters

=8000 x 0.0006213712 miles

=4.97097 miles

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Which is a component of John Dalton’s atomic theory?

Dmitry [639]

Atoms of different elements can be identical

7 0

2 years ago

using the knowledge of the structures of argon and chlorine. Explain why they are both gases at room temperature ?

aleksley [76]

Because at atmospheric pressure the boiling point is below room temperature, just like Oxygen, Nitrogen etc

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2 years ago

An astronaut has a mass of 60kg. Calculate their weight When they are on the surface of the moon.

IceJOKER [234]

Answer:

I think 0kg because they are flying.

7 0

2 years ago

How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)$

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

$334x+x\times 11.976=29553.16$

345.976x = 29553.16

x = 85.4197 kg

Thus,

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0

3 years ago

Activity: A Ferris wheel with a diameter of 60.0 m is moving at a speed of 2.09 m/s. What is the centripetal

GarryVolchara [31]

Answer:

Centripetal acceleration of the wheel is $0.145\ m/s^2$ .

Explanation:

We have,

Diameter of a Ferris wheel is 60 m

Radius of the wheel is 30 m

Speed of the wheel is 2.09 m/s

It is required to find the centripetal acceleration of the wheel. The formula of centripetal acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(2.09)^2}{30}\\\\a=0.145\ m/s^2$

So, the centripetal acceleration of the wheel is $0.145\ m/s^2$ .

5 0

2 years ago