Answer:
AgI, AgBr, AgCl and Ag₂CrO₄
Explanation:
Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:
XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)
<em>Where X is cation and Y is anion.</em>
Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ
The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. <em>Where X is the solubility of the compound.</em>
Replacing in Ksp:
Ksp = [ax]ᵃ [nx]ⁿ
Solving for x, Solubility (S) is defined as:
![S = \sqrt[n+a]{\frac{Ksp}{a^{a} n^n} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5Bn%2Ba%5D%7B%5Cfrac%7BKsp%7D%7Ba%5E%7Ba%7D%20n%5En%7D%20%7D)
For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:
![S = \sqrt[2]{\frac{1.8x10^{-10}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B1.8x10%5E%7B-10%7D%7D%7B1%7D%20%7D)
= 1.34x10⁻⁵M
![S = \sqrt[3]{\frac{1.1x10^{-12}}{4} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1.1x10%5E%7B-12%7D%7D%7B4%7D%20%7D)
= 6.50x10⁻⁵M
![S = \sqrt[2]{\frac{5.4x10^{-13}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B5.4x10%5E%7B-13%7D%7D%7B1%7D%20%7D)
= 7.35x10⁻⁷M
![S = \sqrt[2]{\frac{8.5^{-17}}{1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%5B2%5D%7B%5Cfrac%7B8.5%5E%7B-17%7D%7D%7B1%7D%20%7D)
= 9.22x10⁻⁹M
The lower solubility is the first compound in precipitate, thus, order of precipitation is:
<em>AgI, AgBr, AgCl and Ag₂CrO₄</em>
The balance chemical equation is
2N2 + O2 ---> 2N2O.
We can solve how many moles of nitrous oxide gas from 1.65 moles of nitrogen gas. The balance equation is a critical information to answer this problem since it gives the ratio of nitrous oxide gas produced to the nitrogen used. 2 moles of nitrous oxide gas is produced from 2 moles of nitrogen gas is used. Hence there is 3.30 moles of nitrous oxide gas produced.
Hope This Helps!
:D
One mole contains 6.022×10^23 actually
Answer:
1.07 g of water.
Explanation:
A reaction between an acid and a base makes water and a salt as product.
Our reaction is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Reactants are the acid and the base. Which is the limiting?
2.9 g . 1mol /98 g = 0.0296 moles of acid
3.53 g . 1mol / 40 g = 0.088 moles of base
2 moles of base react to 1 mol of acid
0.088 moles may react to (0.088 . 1)/2 = 0.044 moles of acid
And we only have 0.0296, sulfuric acid is the limiting
Ratio is 1:2. 1 mol of acid can produce 2 moles of water.
Our 0.0296 moles may produce (0.0296 . 2) /1 = 0.0592 moles of water.
We convert moles to mass:
0.0592 mol . 18g /mol = 1.07 g
