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Marina CMI [18]
3 years ago
13

Help please (will give brainliest)

Chemistry
1 answer:
vitfil [10]3 years ago
5 0

Answer:

Gamma

Explanation:

This is because the prticles that are shown can be found in many gamma cancers which mean that that is from gamma

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Give two reasons why the crude product in most reactions is not pure.
Ostrovityanka [42]

Answer:

1) the product may be contaminated by the solvent

2) side reactions may yield unwanted products

3) some reactants may be present in the product if the reaction was incomplete

Explanation:

It is common in chemistry to pass reaction products through purification processes. This is done for a number of reasons.

First of all, some solvents molecules may be attached to the reaction product. These solvent particles must be separated in order to obtain a pure product.

Secondly, some side reactions also yield products that are isolated along with the desired products and these must be separated accordingly.

Finally, some chemical reactions do not go on to completion. This implies that some reactants may still be isolated alongside the product at the end of the reaction.

3 0
4 years ago
Read 2 more answers
Select the appropriate coefficient for O2 when the equation ? O2(g) + ? C5H12(g) → ? CO2(g) + ? H2O(g) is balanced using the sma
Kisachek [45]

Answer:

4O₂ (g) + 1/2C₅H₁₂ (g) →  5/2CO₂ (g)  +  3H₂O (g)

4 would be the smallest possible integer for O₂

Explanation:

The balanced equation is this one:

8O₂ (g) + C₅H₁₂ (g) →  5CO₂ (g)  +  6H₂O (g)

If we divide stoichiometry /2 (the half) we can consider that we use, the smallest possible integers.

8/2O₂ (g) + 1/2C₅H₁₂ (g) →  5/2CO₂ (g)  +  6/2H₂O (g)

4O₂ (g) + 1/2C₅H₁₂ (g) →  5/2CO₂ (g)  +  3H₂O (g)

3 0
3 years ago
Your paragraph containing
Sergeeva-Olga [200]

Answer:

1) Carbon tetrabromide, CBr₄

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are carbon and bromine

b) Specifying the quantity of the element that has more than one atom per mole of the compound, by making mention of the number in Roman

Here there are four bromine atoms per mole which is mentioned as tetra before the cation is mentioned as bromide or ide for-1 oxidation state for  the halogens

c) Indicating the oxidation state of the cation

2) Magnesium oxide, MnO

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are magnesium and oxygen

b) Specifying the quantity of the elements as one each by leaving out the numbering suffix in the name

c) Indicating the oxidation state of the cation, oxygen, as an oxide with a -2 charge

3) Magnesium Nitrate Mn(NO₃)₂

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements and groups in the compound, which are magnesium and bitrate group

b) Specifying the group by the group name which consists of a means to determine the detailed content of the group

c) Indicating the oxidation state of the group, nitrate, which has  with a -1 charge

Explanation:

4 0
3 years ago
A pencil sharpener has a handle with a radius of 1.5 cm. The sharpening mechanism has a radius of 0.5 cm. What is the IMA of the
rosijanka [135]
The answer is A I believe
3 0
4 years ago
Read 2 more answers
Consider the steps in coal gasification: C(coal) + H2O(g) → CO(g) + H2(g) ΔH°rxn = 129.7 kJ CO(g) + H2O(g) → CO2(g) + H2(g) ΔH°r
Volgvan

Answer:

The answer to your question is  ΔHrxn = 0 kJ

Explanation:

  Process

1.- Multiply Equation 1 by 2

           2C(coal) + 2H₂O   ⇒   2CO (g) + 2H₂      ΔH rxn = 259.4 kJ

2.- Sum equation 2

           CO(g)     +  H₂O    ⇒    CO₂ (g)  + H₂ (g)   ΔHrxn = -41 kJ

Result

2C + 3H₂O + CO  ⇒  2CO + 3H₂ + CO₂               ΔHrxn =  218.4 kJ

Simplification

        2C + 3H₂O  ⇒   CO + 3H₂  + CO₂    

3.- Sum equation 3

       CO(g) + 3H₂ (g)  ⇒  CH₄ (g)  +  H₂O  (g)       ΔHrxn = -218.4 kJ

Result

  2C + 3H₂O + 3H₂ + CO  ⇒   CO + 3H₂ + CO₂ + CH₄ + H₂O  

Simplification

                        2C + 2H₂O  ⇒   CO₂ + CH₄         ΔHrxn = 0 kJ

4 0
3 years ago
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