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2 years ago

How many carbon atoms are there in a diamond (pure carbon) with a mass of 55 mg ?

1 answer:

3 0

1 mol of Carbon = 12 grams.
x mol of Carbon = 55 grams

12*x = 1 * 55
x = 55/12
x = 4.583333 mols of carbon

1 mol of anything is 6.02 * 10^23 atoms
4.58333333 mol = x

1/4.5833333 = 6.02 * 10^23/x
x = 4.58333* 6.02*10^23
x = 2.7591 * 10^23 Carbon atoms

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A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0

3 years ago

The essential oil found in cloves, eugenol, can be isolated by steam distillation because it is insoluble in water and has a mea

Damm [24]

We know that:
Molar Mass H2O: 18 g/mol
Molar Mass of Eugenol: 164 g/mol 
Boiling point of H2O: 100 degrees C 
Boiling point of Eugenol: 254 degrees C 
Density of water: 1.0 g/mL 
Density of Eugenol: 1.05 g/mL 

Using formula:
V= [mole fraction x molar mass] / density 

mH20: 0.9947 * 18
= 17.9046 / 1 g/mL
= 17.9046 
morg: 0.0053 * 164
= 0.8692/ 1.05 g/mL
= 0.8278 

V% = Vorg/(Vorg + VH2O) * 100 
(0.8278/18.7324) * 100 = 4.419% 

Yotal volume = 30 mL; therefore,
0.0442 = (volume eugenol/30) 

(m eug/mH2O) = (peug*164/pH2O*18) 
(m eug/30) = (4*164/760*18) 
m eug = about 1.44g and 

volume = mass/density
= 1.44/1.05
= about 1.37 mL

6 0

2 years ago

Jim, Jill, Robert, and Kim each run paper chromatography on an unknown aqueous mixture. Jim gets a red band and a blue band, Jil

Romashka-Z-Leto [24]

Answer:

Robert

Explanation:

There is not more than one colour

4 0

2 years ago

Which of these is a compound??

koban [17]

Potassium ......................

6 0

3 years ago

Read 2 more answers

2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en

dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

lnA=0.4728

logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

Learn more about Arrhenius equation here-

brainly.com/question/12907018

#SPJ4

5 0

1 year ago