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viva [34]
3 years ago
9

How does a scientist explain something when a controlled experiment cannot be carried out

Chemistry
1 answer:
Romashka [77]3 years ago
7 0
<span> We look for evidence. There are numerous natural phenomenon that we can't observe happening in real-time because they happen over large time scales, or large spatial scales. But we can observe the effects of these phenomenon and make predictions about what other effects we should see. </span>
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Predict the energy trend as a substance changes from a solid to liquid to gas on this graph.
Vladimir [108]
Answer:
            Option-A (<span> It would increase from bottom left to top right) is the correct answer.

Explanation:
                   As we know converting solids into liquids and converting liquids into gases require energy. This energy provided increases the energy of the state and its particles start moving with higher velocities. Therefore, the energy of solids will be lower than liquids and gases respectively. While, liquids have greater energy than solids but less energy than gases. And, gases are the most energetic than solids and liquids.</span>
8 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
hammer [34]

B. Magnesium + Hydrogen Sulfide (Reactors) ---->  Magnesium Sulfide + Hydrogen (Products)

8 0
3 years ago
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State the oxidation number of S in <br><img src="https://tex.z-dn.net/?f=H_%7B2%7DSO_%7B3%7D" id="TexFormula1" title="H_{2}SO_{3
Nezavi [6.7K]

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

<h3>Definition of oxidation number</h3>

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

<h3>Oxidation number determination</h3>

To determine the oxidation state of different elements it is necessary to know that:

  • The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
  • The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

<h3>Oxidation numbers of S</h3>

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

<u><em>oxidation numbers of S= 4</em></u>

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

brainly.com/question/8990767

brainly.com/question/6498977

5 0
2 years ago
Read 2 more answers
How is the accuracy of the oxygen determination affected by the addition of a gas into the stream that is reduced by a reaction
Ede4ka [16]

Answer:

Decreased because the method can not distinguish oxygen from the gas added

Explanation:

6 0
3 years ago
Isn’t urgent the first 3 will be marked BRAINIEST
bearhunter [10]

Answer:

Al2(SO4)3 and Mg(OH)2

Explanation:

1. Al has a charge of 3-, and SO4 of 2-

when you cross multiply the charges you get

Al2 and (SO4)3

*the reason theres a bracket around the sulfate ion is that the charge 3 is not for oxygen only, but the entire sulphate ion*

Hence, Al2(SO4)3

2. Mg has a charge of 2- and OH of 1-

again cross multiply

Mg (you dont need to add the 1) and (OH)2

again, the bracket around OH means the charge appiles to Oxygen AND hydrogen

hence, Mg(OH)2

7 0
3 years ago
Read 2 more answers
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