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strojnjashka [21]
3 years ago
5

Explain how you would prepare a solution of sucrose with a molarity of 0.25.

Chemistry
1 answer:
Dimas [21]3 years ago
4 0
Solution of 0.25 M is prepared in two steps,

1) Calculate Amount of Solute:

                                Molar Mass of Solute:  342.3 g/mol

As we know,
                            Molarity  =  Moles / 1 dm³
or,
                            Moles     =  Molarity × 1 dm³
Putting Values,
                            Moles     =  0.25 mol.dm⁻³ × 1 dm³

                            Moles     =  0.25 moles

Now, find out mass of sucrose,
As,               
                            Moles      =   Mass / M.mass
or,
                            Mass       =  Moles × M.mass
Putting Values,
                            Mass       =  0.25 mol × 342.3 g.mol⁻¹

                            Mass       =  85.57 g

2) Prepare Solution:
                               Take Volumetric flask and add 85.57 g of sucrose in it. Then add distilled water up to the mark of 1 dm³. Shake well! The solution prepared is 0.25 M in 1 Liter.
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2 years ago
Based on the trend in the table, hypothesize what the volume of the sample at 400K would be.
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Answer: The volume of sample at 400 K is 285cm^3

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T     (At constant pressure and number of moles)

{\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

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