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Alja [10]
2 years ago
14

A cart accelerating slower when mass was increased. 1st Law - 3rd Law

Chemistry
1 answer:
svet-max [94.6K]2 years ago
8 0

Answer:

Newton's second law

Explanation:

It is mentioning acceleration and mass

Newton's second law's equation = F = m*a

Hope u understood

Please mark brainliest

Thank You

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A candle is 10 cm high and 2 cm in diameter physical or chemical property​
rewona [7]

Answer: Physical property

Explanation: length and dimensions are under physical properties of matter.

3 0
3 years ago
Why do we think mercury has so many tremendous cliffs?
wlad13 [49]

Answer:

it is sticky

Explanation:

hope it helps

4 0
2 years ago
Read 2 more answers
When hydrogen sulfide reacts with oxygen, water and sulfur dioxide are produced. The balanced equation for this reaction is:
VMariaS [17]

Answer:

2H2S + 3O2 → 2SO2 + 2H2O

Explanation:

Step 1: Data given

Hydrogen sulfide = H2S

Oxygen = O2

sulfur dioxide = SO2

water = H2O

Step 2: The unbalanced equation

H2S + O2 → SO2 + H2O

Step 3: Balancing the equation

H2S + O2 → SO2 + H2O

On the left side we have 2x O (in O2) and on the right side we have 3x O (2x in SO2 and 1x in H2O). To balance the amount of O, we have to multiply O2 (on the left side) by 3 and SO2 and H2O on the right side by 3.

H2S + 3O2 → 2SO2 + 2H2O

On the right side we have 4x H and on the left side we have 2x H. To balance the amount of H, we have to multiply H2S by 2.

Now the equation is balanced.

2H2S + 3O2 → 2SO2 + 2H2O

7 0
3 years ago
How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL o
Rama09 [41]

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

<u>Step 1: </u>Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

<u>Step 2:</u> The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

<u>Step 3:</u> Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

<u>Step 4</u>: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

<u>Step 5:</u> Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

7 0
3 years ago
I propose to design a new drug which will act as an inhibitor for an enzyme. If I have used all current information about the me
lilavasa [31]

Answer:

d. A competitive inhibitor, collect kinetic daa both in the presence and absence of inhibitor and watch for a change in Km.

Explanation:

According to the description, the inhibitor was designed in a way when it binds the enzyme, the transition state achieved will be close to the one observed when the substrate binds.

In other words, the aim was to design an inhibitor that will bind the free enzyme in a reversible way, competing with the substrate for the binding sites.

As the inhibitor will be binding the same site as the substrate, the apparent affinity of the enzyme for the substrate will decrease. And the higher the affinity of the inhibitor for the enzyme, stronger the effect it will have over the affinity of the enzyme for the substrate.

Quantitatively speaking, the apparent Km of the enzyme for the substrate will increase with the inhibitor concentration, as the affinity of the enzyme for the substrate decreases.

In summary, what is being engineered is a competitive inhibitor, and the way of knowing if the design was successful, is collecting kinetic data in presence and absence of inhibitor, and watch for changes in the apparent Km.

6 0
2 years ago
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