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suter [353]
3 years ago
10

Plz, answer the Khan Academy question below!

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

I think the answer may be B or D

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Fantom [35]
B the correct answer is
4 0
4 years ago
2x+10=28 <br> What is the solution to this equation
grandymaker [24]

Answer:

Step-by-step explanation:

2x + 10 = 28

Bringing like terms on one side

2x = 28 - 10

2x = 18

x = 18/2 = 9

6 0
3 years ago
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Mr kirk has 6 boxes of 20 oranges how many does she have in total
Semmy [17]

Answer:

120

Step-by-step explanation:

6 x 20 = 120

5 0
3 years ago
Read The question and give Me The answer for number 17
Andre45 [30]

Answer:

( - 5,2);( -2, -3); (4, -1)

So your answer is: A.

3 0
3 years ago
Read 2 more answers
13. A certain town with a population of 100,000 has 3 newspapers: I, II, and III. The proportions of townspeople who read these
Lina20 [59]

Answer:

24,000 people read only one newspaper

12,000 people read at least two newspapers

11,000 people read at least one morning paper plus an evening paper.

64,000 people do not read any newspapers.

10,000 people read only one morning paper and one evening paper.

Step-by-step explanation:

The problem states that:

- 10 percent of the population reads the newspaper I = 10,000

- 8 percent of the population reads the newspaper I and II = 8,000

- 1 percent of the population reads the newspaper I and II an III = 1,000

- 30 percent of the population reads the newspaper III = 30,000

- 2 percent of the population reads the newspaper I and III = 2,000

- 5 percent of the population reads the newspaper III = 5,000

- 4 percent of the population reads the newspaper II and III = 4,000.

Then we have to build the Venn diagram for this: I am going to call

- A the people that read the newspaper I

- B the people that read the newspaper II

- C the people that read the newspaper III

We start this from the people that read each newspaper

A \cap B \cap C = 1,000 - 1,000 people read each newspaper

The people that read only I and II are the number of people that read I and II minus the number of people that read I, II and III. So:

A \cap B = 8,000 - A \cap B \cap C = 8,000 - 1,000 = 7,000

It applies for I and III

A \cap C = 2,000 - A \cap B \cap C = 2,000 - 1,000 = 1,000

And for II and III

B \cap C = 4,000 - A \cap B \cap C = 4,000 - 1,000 = 3,000

The problem states that 10,000 people read the newspaper I, so:

A + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 10000 where A is the number of people that read only the newspaper I. So:

A + 7,000 + 1,000 + 1,000 = 10,000

A + 9,000 = 10,000

A = 1,000

30,000 read the newspaper II, so:

B + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 30,000

B + 7,000 + 3,000 + 1,000 = 30,000

B + 11,000 = 30,000

B = 19,000

5,000 read the newspaper III, so:

C +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 5,000

C + 1,000 + 1,000 + 1,000 = 5,000

C = 2,000

The answers:

a) Find the number of people who read only one newspaper

A + B + C = 1,000 + 21,000 + 2,000 = 24,000

24,000 people read only one newspaper

b) How many people read at least two newspapers

(A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 7,000 + 1,000 + 3,000 + 1,000 = 12,000

12,000 people read at least two newspapers

If I and III are morning papers and II is an evening paper, how many people read at least one morning paper plus an evening paper?

(A \cap B) + (B \cap C) + (A \cap B \cap C) = 7,000 + 3,000 + 1,000 = 11,000

11,000 people read at least one morning paper plus an evening paper.

How many people do not read any newspapers?

There is 100,000 people in the town.

So, the number of people that does not read any newspaper is:

100,000 - (A + B + C + (A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C)) = 100,000 - 36,000 = 64,000

64,000 people do not read any newspapers.

How many people read only one morning paper and one evening paper?

(A \cap B) + (B \cap C) = 7,000 + 3,000 = 10,000

10,000 people read only one morning paper and one evening paper.

3 0
3 years ago
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