Question

In the figure below, the segments cd and ce are tangent to the circle centered at o. Given that od= 4.8 and oc= 7.3, find ce

Answer 1

Answer:

$CE=5.5\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

According to the Perpendicular Tangent Theorem, tangent lines are always perpendicular to a circle's radius at the point of intersection

That means ----> Triangles ODC and OEC are right triangles

In the right triangle OEC

we have

$OE=OD=4.8\ units$ ----> radius of the circle

$OC=7.3\ units$

Applying the Pythagorean Theorem

$OC^2=OE^2+CE^2$

substitute the given values

$7.3^2=4.8^2+CE^2$

$CE^2=7.3^2-4.8^2\\CE^2=30.25\\CE=5.5\ units$