To answer the problem above, I assume that the four-sided figure has equal measure of the sides. Let x be the lengths of each side and the equation for the perimeter is,
P = 4x
Substituting the known values,
70 in = 4x
The value of x is 17.5 in.
Therefore, the each side of the quadrilateral is 17.5 inches long.
Step-by-step explanation:
(-6x +3y=9 )×4
( 10x+4y)×3
-24x +12y =36
30x+12y= -18
-24x+12y- (30x+12y)= 36-(-18)
-54x = 54
x= -1
by using 10x +4y = -6
apply x= -1
-10+4y= -6
4y= -6 +10
4y=4
y=1
so the answer is x=-1 and y= 1
Answer:
9
Step-by-step explanation:
UT^2 = UV * UW
6^2 = (x - 7)(x - 7 + 5)
36 = (x - 7)(x - 2)
36 = x^2 - 2x - 7x + 14
x^2 - 9x - 22 = 0
(x - 11)(x + 2) = 0
x - 11 = 0 or x + 2 = 0
x = 11
UW = x - 7 + 5
UW = 11 - 7 + 5
UW = 9
