An object is shot 8 m/s horizontally from a 7 m tall cliff. How far away does it land?
1 answer:
Answer:
R = 9.52 m
Explanation:
When an object is thrown horizontally from a certain height into the air under the effect of the gravitational force, the movement of the projectile is observed. Projectile motion has two component, Horizontal component and vertical component.
Initially, Projectile motion has only horizontal component and vertical component is equal to zero. Gradually vertical component of velocity increases due to the influence of gravity.
As the ball followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remains constant throughout its motion. So there is no acceleration along horizontal path.
Given data :
Initial velocity = = 8 m/s
Height = h = 7 m
Horizontal range = R = ?
According to 2nd equation of motion
h = t + 0.5gt²
7 = 0.5*9.8*t²
t = 1.19 s
Using R = t
R = 8*1.19
R = 9.52 m
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Answer:
h = 22.35 m
Explanation:
given,
initial speed of the rock,u = 0 m/s
length of the window,l = 2.7 m
time taken to cross the window,t = 0.129 s
Speed of the rock when it crosses the window
v = 20.93 m/s
height of the building above the window
using equation of motion
v² = u² + 2 g h
20.93² = 0² + 2 x 9.8 x h
h = 22.35 m
Hence, the height of the building above the top of window is equal to h = 22.35 m