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goldfiish [28.3K]
3 years ago
13

An object is shot 8 m/s horizontally from a 7 m tall cliff. How far away does it land?

Physics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

R = 9.52 m

Explanation:

When an object is thrown horizontally from a certain height into the air under the effect of the gravitational force, the movement of the projectile is observed. Projectile motion has two component, Horizontal component and vertical component.

Initially, Projectile motion has only horizontal component and vertical component is equal to zero. Gradually vertical component of velocity increases due to the influence of gravity.

As the ball followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remains constant throughout its motion. So there is no acceleration along horizontal path.

Given data :

Initial velocity = v_{i} = v_{i_{x}} = 8 m/s

Height = h = 7 m

Horizontal range = R = ?

According to 2nd equation of motion

h = v_{i_{y}}t + 0.5gt²

7 = 0.5*9.8*t²

t = 1.19 s

Using R = v_{i_{x}}t

R = 8*1.19

R = 9.52 m

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When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive

Explanation:

We know that the relation between the Voltage and the current is given using the Ohm's law, which states that the voltage (V) is directly proportional to the current (I)

Mathematically,

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When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive

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The force required to stretch a Hooke’s-law
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I think this is correct, but I am not entirely certain.

Find the force constant of the spring:

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Which statements describe the relationship between the area and the biodiversity of an ecosystem? Check all that apply. Large ec
snow_tiger [21]

Answer:

A large area of a forest will likely have higher biodiversity than a smaller area of the same forest.

A half acre of rainforest would likely have greater biodiversity than a full acre of desert.

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biodiversity of an ecosystem can be simply explain as the variability that exist in the ecosystem. These are difference that exist between living organism in terms of their habitat, their species and so on. However there exist different relationship between the area of ecosystem and the biodiversity of an ecosystem such that An ecosystem with large area of a forest will likely have higher biodiversity than a smaller area of the same forest.

Another one is that A half acre of rainforest would likely have greater biodiversity than a full acre of desert.

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3 years ago
Read 2 more answers
A 2.45-kg frictionless block is attached to an ideal spring with force constant 355 N/m. Initially the spring is neither stretch
ANTONII [103]

Answer:

A.    A = 0.913 m

B.    amax = 132.24m/s^2

C.    Fmax = 324.01N

Explanation:

When the block is moving at the equilibrium point , its velocity is maximum.

A. To find the amplitude of the motion you use the following formula for the maximum velocity:

v_{max}=A\omega          (1)

vmax = maximum velocity = 11.0 m/s

A: amplitude of the motion = ?

w: angular frequency = ?

Then, you have to calculate the angular frequency of the motion, by using the following formula:

\omega=\sqrt{\frac{k}{m}}           (2)

k: spring constant = 355 N/m

m: mass of the object = 2.54 kg

\omega = \sqrt{\frac{355N/m}{2.45kg}}=12.03\frac{rad}{s}

Next, you solve the equation (1) for A and replace the values of vmax and w:

A=\frac{v}{\omega}=\frac{11.0m/s}{12.03rad/s}=0.913m

The amplitude of the motion is 0.913m

B. The maximum acceleration of the block is given by:

a_{max}=A\omega^2 = (0.913m)(12.03rad/s)^2=132.24\frac{m}{s^2}

The maximum acceleration is 132.24 m/s^2

C. The maximum force is calculated by using the second Newton law and the maximum acceleration:

F_{max}=ma_{max}=(2.45kg)(132.24m/s^2)=324.01N

It is also possible to calculate the maximum force by using:

Fmax = k*A = (355N/m)(0.913m) = 324.01N

The maximum force exertedbu the spring on the object is 324.01 N

4 0
3 years ago
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