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2 years ago

Which object has the most momentum?

2 answers:

6 0

A :-) a.) given - m = 100 kg
v = 2 m/s
Solution -
p = mv
p = 100 x 2
p = 200 kg m/s

b.) Given - m = 100 kg
v = 32 m/s
Solution
p = mv
p = 100 x 32
p = 3200 kg m/s

c.) Given - m = 15 kg
v = 200 m/s
Solution -
p = mv
p = 15 x 200
p = 3000 kg m/s

.:. Option c.) 3000 kg m/s object has the most momentum

Mashutka [201]2 years ago

5 0

C) has the most mass

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I attached an image below with the scheme of the system:

The total force on the charge 2Q is the sum of the contribution of the forces between 2Q and the other charges:

$F_T=F_Q+F_{3Q}+F_{4Q}\\\\F_T=k\frac{(Q)(2Q)}{R_1}\hat{i}+k\frac{(3Q)(2Q)}{R_2}\hat{j}+k\frac{(4Q)(2Q)}{R_3}[cos\theta \hat{i}+sin\theta \hat{j}]$

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$F_T=k\frac{2Q^2}{L}\hat{i}+k\frac{6Q^2}{L}\hat{j}+k\frac{8Q^2}{\sqrt{2}L}[cos(45\°)\hat{i}+sin(45\°)\hat{j}]\\\\F_T=k\frac{2Q^2}{L}\hat{i}+k\frac{6Q^2}{L}\hat{j}+k\frac{8Q^2}{\sqrt{2}L}[\frac{\sqrt{2}}{2}\hat{i}+\frac{\sqrt{2}}{2}\hat{j}]\\\\F_T=6k\frac{Q^2}{L}\hat{i}+10k\frac{Q^2}{L}\hat{j}=2k\frac{Q^2}{L}[3\hat{i}+5\hat{j}]$

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$\theta=tan^{-1}(\frac{5}{3})=59.03\°$

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