1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sunny_sXe [5.5K]
3 years ago
12

Why do astronauts need to wear pressurized suits in space?

Physics
1 answer:
SashulF [63]3 years ago
6 0
The correct answer is C , because the space is vacuum and his body can explode and for this reason,  the astronaut need a special costum to be protected. It's the same on the moon, because there is no atmosphere 
You might be interested in
Two loudspeakers 42.0 m apart and facing each other emit identical 115 Hz sinusoidal sound waves in a room where the sound speed
Tems11 [23]

Answer:

She passes through a loud spot at x = 19.5m from the first speaker. Constructive interference occurs here.

At the quiet spot destructive interference occurs. The minimum distance for this to occur is 20.25 from the first speaker.

Explanation:

3 0
3 years ago
A man stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. What is the velocity of the man accordi
RSB [31]
The velocity is 0.3 m/s South.
3 0
2 years ago
Read 2 more answers
A vacuum tube diode consists of concentric cylindrical electrodes, the negative cathode and the positive anode. Because of the a
DENIUS [597]

Answer:

   C = 4,174 10³ V / m^{3/4} ,  E = 7.19 10² / ∛x,    E = 1.5  10³ N/C

Explanation:

For this exercise we can calculate the value of the constant and the electric field produced,

Let's start by calculating the value of the constant C

           V = C x^{4/3}

           C = V / x^{4/3}

            C = 220 / (11 10⁻²)^{4/3}

            C = 4,174 10³ V / m^{3/4}

To calculate the electric field we use the expression

            V = E dx

             E = dx / V

             E = ∫ dx / C x^{4/3}

            E = 1 / C  x^{-1/3} / (- 1/3)

            E = 1 / C (-3 / x^{1/3})

We evaluate from the lower limit x = 0 E = E₀ = 0 to the upper limit x = x, E = E

            E = 3 / C     (0- (-1 / x^{1/3}))

            E = 3 / 4,174 10³   (1 / x^{1/3})

           E = 7.19 10² / ∛x

for x = 0.110 cm

          E = 7.19 10² /∛0.11

          E = 1.5  10³ N/C

6 0
3 years ago
A 2.13-kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 5.00 N
ANTONII [103]

Answer:

17.54N in -x direction.

Explanation:

Amplitude (A) = 3.54m

Force constant (k) = 5N/m

Mass (m) = 2.13kg

Angular frequency ω = √(k/m)

ω = √(5/2.13)

ω = 1.53 rad/s

The force acting on the object F(t) = ?

F(t) = -mAω²cos(ωt)

F(t) = -2.13 * 3.54 * (1.53)² * cos (1.53 * 3.50)

F(t) = -17.65 * cos (5.355)

F(t) = -17.57N

The force is 17.57 in -x direction

5 0
3 years ago
The process by which metamorphic rock changes to igneous rock begins with?
Strike441 [17]
Melting, as igneous rock is magma or lava that has cooled and hardened.
5 0
3 years ago
Other questions:
  • You have a neutral balloon. What is its charge after 12000 electrons have been removed from it? The elemental charge is 1.6 × 10
    11·1 answer
  • Can anyone help me with this problem? It is -2.1??
    12·1 answer
  • What is the application for reflection of waves?
    6·1 answer
  • A car weighing 10.7 kN and traveling at 13.6 m/s without negative lift attempts to round an unbanked curve with a radius of 64.0
    6·1 answer
  • On my bike, I was able to travel 40 miles in one hour. From this information, we can determine the bike's
    10·2 answers
  • Which of the following are likely to form a covalent bond?
    15·2 answers
  • Fibanachi's racio. What is it?
    5·1 answer
  • Find the unit vector in the direction of resultant vector A=2i-3j+k , B=i+j+2k , C=3i-2j+4k​
    10·1 answer
  • ERCRSOVOS - Table tennis footwork that is useful in this moment to cover a large distance quickly (SCRAMBLED)PE)
    5·1 answer
  • A cable that weighs 4 lb/ft is used to lift 1000 lb of coal up a mine shaft 700 ft deep. Find the work done.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!