Express 76.874 inches in miles

Is the following true or false? Why?<br> x < 8 is the same as 8 < x

wolverine [178]

Answer:

False.

Step-by-step explanation:

X can not be less than 8 and also greater than 8 and the same time.

5 0

3 years ago

bag a has $3$ white marbles and $4$ black marbles. bag b has $6$ yellow marbles and $4$ blue marbles. bag c has $2$ yellow marbl

r-ruslan [8.4K]

Answer:

BALSS

Step-by-step explanation:

GURL Y DO YOU HAVE SO MANY MARBELS ???

4 0

1 year ago

I really need help it’s due in two days

Bumek [7]

Answer:

Step-by-step explanation:

The answer is "Impossible to solve" , because there is no rule for function at point x = 7 . The given function has domain ( - ∞ , 2 ) ∪ { 2 } ∪ ( 2 , 7 ) ⇒ 7 is not a part of domain!!!

8 0

3 years ago

What does the symbol for factorial function mean

Phoenix [80]

The factorial function is a mathematical formula represented by an exclamation mark "!". In the Factorial formula you must multiply all the integers and positives that exist between the number that appears in the formula and the number 1.

7 0

2 years ago

Read 2 more answers

A cellphone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new

stiv31 [10]

Answer:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=135 represent the subscribers that would upgrade to a new cellphone at a reduced cost

$\hat p=\frac{135}{500}=0.27$ estimated proportion of subscribers that would upgrade to a new cellphone at a reduced cost

$p_o=0.2$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.2 or not.:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

6 0

4 years ago