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3 years ago

10

50 points, question is down below.

2 answers:

maks197457 [2]3 years ago

6 0

$\dfrac{\frac{3}{x-1}-4}{2-\frac{2}{x-1}}=\left(\dfrac{3}{x-1}-\dfrac{4(x-1)}{x-1}\right):\left(\dfrac{2(x-1)}{x-1}-\dfrac{2}{x-1}\right)\\\\=\dfrac{3-4x+4}{x-1}\cdot\dfrac{2x-2-2}{x-1}=\dfrac{-4x+7}{x-1}\cdot\dfrac{x-1}{2x-4}\\\\=\dfrac{-4x+7}{1}\cdot\dfrac{1}{2(x-2)}=\dfrac{-4x+7}{2(x-2)}$

kozerog [31]3 years ago

4 0

Answer:

the second one

Step-by-step explanation:

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