Describe an alternate method for determining the molar concentration of your unknown sample of copper (ii) sulfate solution, usi
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Answer:
2SO₂(g) + O₂(g) ↔ 2SO₃(g) Kc = 15M⁻¹
The sets are:
(A) (SO₂)=0.16M; (O₂)=0.20M; (SO₃)=0.50M
(B) (SO₂)=0.20M; (O₂)=0.60M; (SO₃)=0.60M
(C) (SO₂)=0.50M; (O₂)=0.60M; (SO₃)=0.15M
The reaction quotient is
Q =
- If Q < Kc, then the reaction will proceed towards the right (products)
- If Q > Kc, then the reaction will proceed towards the left (reactants)
- If Q = Kc, then we're at equilibrium.
Now we <u>calculate Q for each of the sets</u>:
(A) Q = 0.50² / (0.16²*0.20) = 48.8
Q > Kc. So the reaction will proceed towards the left.
(B) Q = 0.60² / (0.20²*0.60) = 15
Q = Kc. So the reaction is at equilibrium.
(C) Q = 0.15² / (0.50²*0.60) = 0.15
Q < Kc. So the reaction will proceed towards the right.