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3 years ago

13

Break apart the elements and count the atoms

10" align="absmiddle" class="latex-formula">

1 answer:

Irina-Kira [14]3 years ago

4 0

Answer:

Explanation:

6 carbon 10 hydrogen 6 + 10 = 16

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At what pressure does the mean free path of argon at 20 degrees celsius become comparable to the diameter of a 100 cm3vessel th

inn [45]

Answer:

The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa

Explanation:

<u>Step 1</u>: Calculate the volume of a spherical container V

V = (4π*r³)/3

r = (3V/4π)^1/3

2r = d = 2*(3V/4π)^1/3

with r= radius

with d= diameter

The diameter is:

d= 2*(3V/4π)^1/3

d= 2*(3*100cm³/4π)^1/3

d= 5.76 cm

<u>Step2 </u>: Define the free path lambda λ of argon

with λ =k*T/ σp

with p = kT/σλ

with T= temperature = 20°C = 293.15 Kelvin

with k = Boltzmann's constant = 1.381 * 10^-23 J/K

with p = the atmospheric pressure

with σ = 0.36 nm²

p = kT/σλ

p = (1.38 * 10^-23 J*K^-1 * 1Pa *m³/1J)*(293,15K) /(0.36 nm²*(10^-9/ 1nm)² *(5.76cm* 10^-2m/1cm)

p = 0.195 Pa

The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa

5 0

3 years ago

A family is traveling south to Florida for a 5 day Disney vacation. The are traveling 105 km per hour during the trip. Is this a

zubka84 [21]

Answer:

Velocity, because it has both magnitude and direction.

Step-by-step explanation:

Velocity is the rate at which an object changes position in a specific direction. It has both magnitude and direction.

The family is travelling south at 105 km/h. This is an example of velocity, because it has magnitude (105 km/h) and direction (south).

3 0

3 years ago

How are matter and substances related?

Nitella [24]

Matter and substance are definitely related. All substances are matter but all matters are not substance. A matter can consist of numerous substances. Matter is generally a loose term used in respect to a substance. Any physical object can be casually called a matter. Matter and substance are sometimes used for the same context, but it is completely wrong. Numerous examples have already proved that a matter may or may not be a substance depending on its physical nature, but a substance is always a matter.

8 0

3 years ago

A student mixes baking soda and vinegar in a glass. Are there any new substances created from this mixture?

Anni [7]

Answer:

Explanation:

1. A student mixes baking soda and vinegar in a glass. The results are shown at left. ... Yes I do belive that new substances are being formed because there is a chemical reaction between the baking soda and vinegar turning it into a bubbly substances instead of a powder and liquid.

4 0

3 years ago

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h

statuscvo [17]

Explanation:

First, calculate the moles of $CO_{2}$ using ideal gas equation as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $\frac{mass}{volume}$

Hence, mass of water will be as follows.

Density = $\frac{mass}{volume}$

0.998 g/ml = $\frac{mass}{3.26 ml}$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{3.25 g}{18.02 g/mol}$

= 0.180 mol

Moles of hydrogen = $0.180 \times 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $\frac{mass}{12 g/mol}$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.95 g}{16 g/mol}$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_{3}H_{6}O$ .

Thus, we can conclude that empirical formula of the given compound is $C_{3}H_{6}O$ .

6 0

4 years ago