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True [87]
3 years ago
14

The formula of strontium

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
6 0
Sr, because they are just basically asking for it so it is just Sr
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If the half-life of technitium-104 is 18.0 min, how much of a 14.2-g sample will remain after 72 minutes?
Debora [2.8K]
The decay of a radioactive isotope can be predicted using the formula: A = Ao[2^(-t/T_0.5)] where A is the amount after time t, Ao is the original amount and T_0.5 is the half-life. Using the equation and the given values, 0.888 g of the sample will remain after 72 minutes. 
3 0
3 years ago
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What does radiochemical dating do
Elenna [48]

Answer:

Radiometric dating, often called radioactive dating, is a technique used to determine the age of materials such as rocks.

5 0
2 years ago
A fossilized leaf contains 24% of its normal amount of carbon 14. how old is the fossil (to the nearest year)? use 5600 years as
sergij07 [2.7K]
The Half life is the time taken for a radioisotope or a radioactive substance to decay by half its original amount. The half life of carbon 14 is 5600 years. 
Original mass is 100%
Remaining amount is 24% 
Therefore; 0.24 = 1 × (1/2)^n
                     n = log 0.24/log 0.5
                        = 2.06
therefore, the age of the fossil is 5600×2.06
 = 11529.8 
 ≈ 11529 years

7 0
3 years ago
How many moles are in 2.5L of 1.75 M Na2CO3
Natasha_Volkova [10]

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

M=n/V

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

n=V*M

Thus, we plug in the given data to obtain:

n=2.5L*1.75mol/L=4.4mol

Best regards!

4 0
2 years ago
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HELP. NO FAKE ANSWERS. I WILL REPORT. I AM CONFUSED AND NEED HELP. FILL IN THE NOT FILLED BOXES POR FAVOR.
SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
       = 0.0075 moles × 1000/20
       = 0.375 M

7 0
3 years ago
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