Answer:
138 mg
Explanation:
A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, <em>155 milligrams of calcium per kilogram of drinking water</em>. We need to find the maximum amount of calcium in 890 g of drinking water.
Step 1: Convert the mass of drinking water to kilograms.
We will use the relation 1 kg = 1000 g.
Step 2: Calculate the maximum amount of calcium in 0.890 kg of drinking water
Answer : The equilibrium constant for the reaction is, 0.1133
Explanation :
First we have to calculate the concentration of .
Now we have to calculate the dissociated concentration of .
The balanced equilibrium reaction is,
Initial conc. 1.731 M 0
At eqm. conc. (1.731-x) (2x) M
As we are given,
The percent of dissociation of =
= 1.2 %
So, the dissociate concentration of =
The value of x = 0.2077 M
Now we have to calculate the concentration of at equilibrium.
Concentration of = 1.731 - x = 1.731 - 0.2077 = 1.5233 M
Concentration of = 2x = 2 × 0.2077 = 0.4154 M
Now we have to calculate the equilibrium constant for the reaction.
The expression of equilibrium constant for the reaction will be :
Now put all the values in this expression, we get :
Therefore, the equilibrium constant for the reaction is, 0.1133