What is the process by which individuals that are better adapted to their evnviroment are more likely to survive and reproduce?
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The Formula of Acetone is 
To find the Mass Molar of a compound, you add the Atomic weights of it's atoms.
If you check the Periodic table:
Atomic Weight of Carbone C: 12.0107
Atomic Weight of Hydrogen: 1.00794
Atomic Weight of Oxygen: 15.9994
So, you got:
Total Atomic Weight of Carbone in Acetone: 12.0107 * 3 = 36.0321
Total Atomic Weight of Hydrogen in Acetone: 1.00794 * 6 = 6.04764
Total Atomic Weight of Oxygen in Acetone = 15.9994 * 1 = 15.9994
Now, you add this numbers
36.0321 + 6.04764 + 15.9994 = 58.07914
So, the Molar Mass of Acetone is 58.09714 g/mol
Hope this Helps :D
To find the Mass Molar of a compound, you add the Atomic weights of it's atoms.
If you check the Periodic table:
Atomic Weight of Carbone C: 12.0107
Atomic Weight of Hydrogen: 1.00794
Atomic Weight of Oxygen: 15.9994
So, you got:
Total Atomic Weight of Carbone in Acetone: 12.0107 * 3 = 36.0321
Total Atomic Weight of Hydrogen in Acetone: 1.00794 * 6 = 6.04764
Total Atomic Weight of Oxygen in Acetone = 15.9994 * 1 = 15.9994
Now, you add this numbers
36.0321 + 6.04764 + 15.9994 = 58.07914
So, the Molar Mass of Acetone is 58.09714 g/mol
Hope this Helps :D
━┈─────────────────────┈━
<h3>First we find out the freezing point:</h3>→(-23.0)-(0.0_
→-23.0 degrees C
<h3>Calculate target Colligative Molarity:</h3>→ -23=1.86 * Cm
→ 12.37= Cm.
→i* molality
→i= 1
→12.37= 1*m
→12.37= m
<h3>molality= moles of solute(C2H6O2)/kg of solvent water</h3>12.37m= moles C2H6O2/ 10.0kg water
123.7= moles of C2H6O2
123.7moles C2H6O2 * 62.26g C2H6O2
<h2>= 7701.56 g of C2H6O2</h2>━┈─────────────────────┈━
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