Question

2. What mass of sodium chloride is produced when chlorine gas reacts with 2.29 grams of sodium iodide? The unbalanced equation is given below: Nal (s) + Cl, (g) → NaCl (s) + 1, (g)​

Answer 1

Answer:

0.88g

Explanation:

The reaction equation:

         2NaI  + Cl₂   →    2NaCl  + I₂

Given parameters:

Mass of Sodium iodide = 2.29g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we work from the known to the unknown.

First find the number of NaI from the mass given;

   Number of moles  = $\frac{mass}{molar mass}$  

          Molar mass of NaI  = 23 + 126.9  = 149.9g/mol

 Now insert the parameters and solve;

     Number of moles  = $\frac{2.29}{149.9}$   = 0.015mol

So;

 From the balanced reaction equation;

            2 moles of NaI produced 2 moles of NaCl

          0.015mole of NaI will produce 0.015mole of NaCl

Therefore;

      Mass  = number of moles x molar mass

      Molar mass of NaCl = 23 + 35.5  = 58.5g/mol

Now;

      Mass of NaCl  = 0.015 x 58.5  = 0.88g