The bearing of point X <u>from</u> point Z is 285°
<h3>Calculating bearings </h3>
From the question, we are to determine the bearing of point X from point Z.
Consider the diagram attached
The bearing of point X <u>from</u> point Z is the measure of the angle from the North of Z in the <u>clockwise direction</u> to the line that goes to X.
That is,
The bearing of point X from point Z = 270° + 15°
The bearing of point X from point Z = 285°
Hence, the bearing of point X from point Z is 285°
Learn more on Calculating bearings here: brainly.com/question/22719608
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Answer: Hello!
A second order differential equation has the next shape:

where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.
And is called homogeneus when g(t) = 0, so you have:

Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.
Answer:
x^2 + 2xy + y ^2
Step-by-step explanation:
A = a^2
a = x + y
(x + y) + (x + y)
x^2 + xy + xy + y^2
x^2 + 2xy + y ^2