One Ba2+ and two Br- ions will be there.
Answer is 3
To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:
<span>76.9 g I2 (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol ) = 1.82x10^23
79.9 g Br2 (1 mol / 159.81 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
6 g C (1 mol / 12 g)</span>(6.022x10^23 particles / 1 mol ) = 3.011x10^23<span>
13.01 g CH4 ( 1 mol / 16.04 g )</span>(6.022x10^23 particles / 1 mol ) = 4.88x10^23 particles
Therefore, the answers are Br2 and C.
0.0340 g O2
<em>Step 1.</em> Write the balanced chemical equation
4Fe(OH)^(+) + 4OH^(-) + O2 + 2H2O → 4Fe(OH)3
<em>Step 2</em>. Calculate the moles of Fe^(2+)
Moles of Fe^(2+) = 50.0 mL Fe^(2+) × [0.0850 mmol Fe^(2+)/1 mL Fe^(2+)]
= 4.250 mmol Fe^(2+)
<em>Step 3</em>. Calculate the moles of O2
Moles of O2 = 4.250 mmol Fe^(2+) × [1 mmol O2/4 mmol Fe^(2+)]
= 1.062 mmol O2
<em>Step 4</em>. Calculate the mass of O2
Mass of O2 = 1.062 mmol O2 × (32.00 mg O2/1 mmol O2) = 34.0 mg O2
= 0.0340 g O2
Answer:
Theoretical yield for Si = 2586.55*28.09= 72.7 Kg
Percentage yield is =2356.71/2586.55=91.11%
Explanation:
So the chemical equation for this reaction would be SiO2 + 2C = Si + CO
so n(SiO2)=m(SiO2)/M(SiO2)=155400/60.08=2586.55 mol
n(C)=m(C)/M(C)=77400/12.01=6444.63 mol
So Carbon is in exes.
n(Si)=m(Si)/M(Si)=66200/28.09= 2356.71 mol
Theoretical yield for Si = 2586.55*28.09= 72.7 Kg
Percentage yield is =2356.71/2586.55=91.11%
