What type of System interact with its environment
1 answer:
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Answer:
(a)Velocity of wind = 35 j
(b)Velocity of jet relative to air = 425 i
(c)True velocity of jet = 425 i + 35 j
(d)True speed of jet = = 426.88 mi/h
Direction of jet is, ∅ = = 5.38°
Explanation:
We can represent east direction by i and north direction by j.
The jet has a relative speed of 425 mi/h relative to the air.
The wind is blowing due north with a speed of 35 mi/h = 35 j
425 mi/h is the relative speed with respect to wind that is
Velocity of jet wrt wind= =
425 i = - 35 j
= 425 i + 35 j
(a)Velocity of wind = 35 j
(b)Velocity of jet relative to air = 425 i
(c)True velocity of jet = 425 i + 35 j
(d)True speed of jet = = 426.88 mi/h
Direction of jet is,
∅ = = 5.38°
Answer:
a = 1600 m / s²
Explanation:
For this exercise we use the kinematics relations,
v² = v₀² + 2 a x
where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m
a =
let's calculate
a =
a = 1600 m / s²
Answer:
The observed wavelength on Earth from that hydrogen atom is .
Explanation:
Given that,
The actual wavelength of the hydrogen atom,
A hydrogen atom in a galaxy moving with a speed of,
We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :
is the observed wavelength
So, the observed wavelength on Earth from that hydrogen atom is . Hence, this is the required solution.