1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irinina [24]
2 years ago
5

If the volume on your TV is low, turning the volume up one click of the remote control will make the TV seem louder than if the

volume were already relatively high. This ratio (turning up the volume by one click relative to the TV's overall volume) can be quantified as the __________ fraction.
A. Fechner
B. Young
C. Weber
D. Helmholtz
Physics
1 answer:
marusya05 [52]2 years ago
7 0

From what we know, we can confirm that this ratio (turning up the volume by one click relative to the TV's overall volume) can be quantified as the Weber fraction.

<h3>What is the Weber fraction?</h3>

This fraction describes the ratio needed for change to a stimulus in which the change is just barely noticeable. This question is a prime example in that it seeks to find out just how low of a difference is needed in TV volume in order for the difference to be noticeable.

Therefore, we can confirm that this ratio (turning up the volume by one click relative to the TV's overall volume) can be quantified as the Weber fraction.

To learn more about Weber visit:

brainly.com/question/5004433?referrer=searchResults

You might be interested in
4 US regions where major aquifers can be found
professor190 [17]
Answer:

Nebraska, South Dakota, North Dakota, and Montana.
6 0
3 years ago
Atoms gain the same electron configuration as noble gases by
Nesterboy [21]
Thr answer is D losing or gaining electons
3 0
3 years ago
Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?
FrozenT [24]
Should be 10 cm cubed
6 0
3 years ago
Read 2 more answers
If a negatively charged particle moves into a magnetic field traveling in a straight line, how would you expect its motion to ch
gayaneshka [121]
Hello
the answer is a
7 0
4 years ago
Read 2 more answers
You are holding one end of an elastic cord that is fastened to a wall 3.0 m away. You begin shaking the end of the cord at 2.3 H
Karo-lina-s [1.5K]

Answer:

Time take to fill the standing wave to the entire length of the string is 1.3 sec.

Explanation:

Given :

The length of the one end x= 3m, frequency of the wave f = 2.3 Hz, wavelength of the wave λ = 1 m.

Standing wave is the example of the transverse wave, standing wave doesn't transfer energy in a medium.

We know,

∴ v = fλ

Where v = speed of the standing wave.

also, ∴ v=\frac{x}{t}

where t = time take to fill entire length of the string.

Compare above both equation,

⇒   t = \frac{3}{2.3} sec

     t = 1.3sec

Therefore, the time taken to fill entire length 0f the string is 1.3 sec.

7 0
3 years ago
Other questions:
  • 4. A 505-turn circular-loop coil with a diameter of 15.5 cm is initially aligned so that
    8·2 answers
  • How many new moons will occur in 2016?
    14·2 answers
  • How close is the nearest star in miles?
    11·1 answer
  • What happens to the current supplied by the battery when you add an identical bulb in parallel to the original bulb?
    15·1 answer
  • A wire of radius 0.6 cm carries a current of 94 A that is uniformly distributed over its cross-sectional area. Find the magnetic
    14·1 answer
  • Who might benefit from this claim?
    5·1 answer
  • What makes the eardrum vibrate?
    9·1 answer
  • A radio signal has a frequency of 1.023 x 108 HZ. If the speed of the signal in air is 2.997 x 108m/s, what is the wavelength of
    11·1 answer
  • The place you get your hair cut has two nearly parallel mirrors 6.5 m apart. As you sit in the chair, your head is 2.0 m from th
    14·1 answer
  • Less massive molecules tend to escape from an atmosphere more often than more massive ones because
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!