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snow_lady [41]
3 years ago
10

Consider a solenoid of length L, N windings, and radius b (L is much longer than b A current I). is flowing through the wire. If

the length of the solenoid became twice as long (2L), and all other quantities remained the same, the magnetic field inside the solenoid would _________.
Physics
1 answer:
wolverine [178]3 years ago
5 0

Answer:

The magnetic field inside the solenoid would decrease by a factor of 2.

Explanation:

The magnetic field, B, of a solenoid of length L, N windings, and radius b with a current, I, flowing through it is given as:

B = (N * r * I) / L

If the length of the solenoid is doubled, 2L,the magnetic field becomes:

B2 = (N * r * I) / 2L

B2 = ½ B

The magnetic field will decrease by a factor of 2.

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A student places her 490 g physics book on a frictionless table. She pushes the book against a spring, compressing the spring by
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Answer:

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Explanation:

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to find out

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solution

we know energy is conserve so

we can say

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\frac{1}{2}*k*x^2 = \frac{1}{2}*m*v^2    ..................1

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