Answer: 9/8
Step-by-step explanation:
Answer:
The required thickness of the tank wall is 87.7668 mm.
Step-by-step explanation:
Given :
Volume of vessel is V=1.5 m³.
A spherical pressure vessel is of compressed natural gas at P=22 MPa.
If the tank is made of A516 grade 60 steel with a maximum normal stress 150 MPa.
i.e.
To find : What is the required thickness of the tank wall?
Solution :
The diameter of the vessel is given by,
Convert into mm,
The thickness of the wall tank is given by,
Therefore, the required thickness of the tank wall is 87.7668 mm.
There are 62.9 students and 11.1 teachers.
Weird, I know. But my math is bullet-proof.
A is located at (2,5)
A' is located at (5,7)
Subtract the X's and then the Y's to get how much it moved:
5-2 = 3 unit shift to the right.
7-5 = 2 unit shift up.
The answer would be A.
13. to make our table, we sub in any value for x and solve for y
y = -2x - 3
lets say x = 0
y = -2(0) - 3
y = -3....so when x = 0, y = -3
lets say x = 1
y = -2(1) - 3
y = -2 - 3
y = -5...so when x = 1, y = -5
lets say x = 2
y = -2(2) - 3
y = -4 - 3
y = -7....so when x = 2, y = -7
so ur table will look like this...
x 0 1 2
----
y -3 -5 -7
u can find more points if u need to by just repeating the steps I did
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14. to find the x intercept, sub in 0 for y and solve for x
y = -2x - 3
0 = -2x - 3
2x = -3
x = -3/2...so the x intercept is (-3/2,0)
to find the y intercept, sub in 0 for x and solve for y
y = -2x - 3
y = -2(0) - 3
y = -3....so ur y intercept is (0,-3)