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Fudgin [204]
3 years ago
9

Through what basic mechanism is 2-methylcyclohexanol converted to 1-bromo-1-methylcyclohexane when treated with HBr

Chemistry
1 answer:
evablogger [386]3 years ago
8 0

Answer:

Sn1 mechanism reaction

Explanation:

In this case, we have to start with the <u>protonation</u> of the "OH" group by the attack of the lone pairs in the alcohol group to the "H" in the HBr producing a <u>positive charge in the oxygen</u>. Then, water is produced and a <u>carbocation</u> is generated. This carbocation can be stabilized by a <u>hydride shift</u>. We can move a hydrogen atom to the positive charge and we will obtain a <u>tertiary carbocation</u>. Finally, the Br^- will attack to produce the final <u>halide</u>.

See figure 1.

I hope it helps!

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Determine the element, given the number of protons in an atom
LUCKY_DIMON [66]
You can determine an element based on its protons due to the atomic number.
Atomic number is the number of protons in an atom and you can locate it on your periodic table as the number above the letter. Each element has a different number of protons and because of that you can find the element on the periodic table based on its atomic number.
8 0
3 years ago
How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution?
Basile [38]

Answer:

235 g

Explanation:

From the question;

  • Volume is 400.0 mL
  • Molarity of a solution is 4.25 M

We need to determine the mass of the solute K₂CO₃,

we know that;

Molarity = Number of moles ÷ Volume

Therefore;

First we determine the number of moles of the solute;

Moles = Molarity × volume

Moles of  K₂CO₃ = 4.25 M × 0.4 L

                           = 1.7 moles

Secondly, we determine the mass of  K₂CO₃,

We know that;

Mass = Moles × Molar mass

Molar mass of  K₂CO₃, is 138.205 g/mol

Therefore;

Mass = 1.7 moles × 138.205 g/mol

         = 234.9485 g  

         = 235 g

Thus, the mass of  K₂CO₃ needed is 235 g

7 0
4 years ago
How is a kilogram of cotton balls similar to a kilogram of bricks
Nutka1998 [239]

Answer:

because they are both a kilogram

Explanation:

7 0
3 years ago
How many molecules of ethane ( C2H6) are present in 0.197g of C2H6?
Brut [27]

Answer:

3.945 x 10²¹ molecules

Explanation:

  • Firstly, we need to calculate the no. of moles using the relation:
  • n = mass/molar mass = (0.197 g)/(30.07 g/mol) = 6.55 x 10⁻³ mol.
  • It is known that every 1.0 mol of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).
  • <em>∴ 0.197 g of C₂H₆ will contain</em> = (6.55 x 10⁻³ mol)(6.022 x 10²³) = <em>3.945 x 10²¹ molecules.</em>
4 0
3 years ago
Read 2 more answers
An aqueous solution containing 17.5 g of an unknown molecular compound in 100.g water was found to have a freezing point of-1.8°
Zigmanuir [339]

Answer:

The answer to your question is 178.6 g

Explanation:

Data

ΔT = 1.8 °C

mass = 17.5 g

mass of water = 100 g

Kc = 1.86

Process

1.- Calculate the molality using the following formula

    ΔTc = mKc

solve for m

    m = ΔTc/Kc

substitution

     m = 1.8/1.86

result

     m = 0.968

2.- Calculate the number of moles

    m = # of moles/kg of solvent

kg of solvent = 0.1 kg

     # of moles = m x kg of solvent

     # of moles = 0.968 x 0.1

     # of moles = 0.0968

3.- Calculate the molar mass

        x g molar mass --------------------- 1 mol

       17.5 g                  --------------------- 0.0968 moles

       x = (1 x 17.5)/0.0968

      x = 178.6 g

             

4 0
3 years ago
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