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2 years ago

When 5ml of 30% H2O2 is decomposed into water and oxygen, how many grams of oxygen and how many grams of water are left?

Chemistry

1 answer:

joja [24]2 years ago

5 0

The mas of the products are given below:

mass of oxygen produced = 0.7056 g of oxygen
mass of water produced = 0.794 g of hydrogen

<h3>How many moles are there in 5 ml of 30% of hydrogen peroxide?</h3>

The moles of hydrogen peroxide in 5 ml of 30% of hydrogen peroxide is calculated using the formula:

Moles = concentration * volume

Molarity of 30% of hydrogen peroxide = 8.82 mol/L

Moles = 8.82 * 5/1000 = 0.0441 moles

The equation of the the decomposition of hydrogen peroxide is given as:

2 H₂O₂ -----> 2 H₂O + O₂

Based on the mole ratio;

mass of oxygen produced = 0.0441/2 * 32 g = 0.7056 g of oxygen

mass of water produced = 0.0441 * 18 g = 0.794 g of hydrogen

Therefore, the mass of the products of the decomposition of hydrogen peroxide is determined from the mole ratio of the reaction.

Learn more about mole ratio at: brainly.com/question/19099163

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A 0.334 g sample of an unknown halogen occupies 109 mL at 398 K and 1.41 atm. What is the identity of the halogen?

kolezko [41]

We can use the ideal gas law equation for the above reaction to find the number of moles present
PV = nRT
P - pressure - 1.41 atm x 101325 Pa/atm = 142 868 Pa
V - 109 x 10⁻⁶ m³
R - 8.314 Jmol⁻¹K⁻¹
T - 398 K
substituting the values in the equation
142 868 Pa x 109 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 398 K
n = 4.70 x 10⁻³ mol
number of moles = mass present / molar mass
molar mass = mass / number of moles
= 0.334 g/ 4.70 x 10⁻³ mol = 71.06 g/mol
halogens exist as diatomic molecules
Therefore atomic mass - 71.06 / 2 = 35.5
halogen with 35.5 g/mol is Cl
unknown halogen is Cl

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2 years ago

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snow_lady [41]

Answer:

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2 years ago

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3 years ago

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Naya [18.7K]

Answer:

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The formula for a compound of Li₊ ions and Br_ ions is written LiBr. Why can't it be written Li₂Br? Why isn't it written BrLi?

bogdanovich [222]

Answer:

Explanation:

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2 years ago

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