The mas of the products are given below:
- mass of oxygen produced = 0.7056 g of oxygen
- mass of water produced = 0.794 g of hydrogen
<h3>How many moles are there in 5 ml of 30% of hydrogen peroxide?</h3>
The moles of hydrogen peroxide in 5 ml of 30% of hydrogen peroxide is calculated using the formula:
Moles = concentration * volume
Molarity of 30% of hydrogen peroxide = 8.82 mol/L
Moles = 8.82 * 5/1000 = 0.0441 moles
The equation of the the decomposition of hydrogen peroxide is given as:
2 H₂O₂ -----> 2 H₂O + O₂
Based on the mole ratio;
mass of oxygen produced = 0.0441/2 * 32 g = 0.7056 g of oxygen
mass of water produced = 0.0441 * 18 g = 0.794 g of hydrogen
Therefore, the mass of the products of the decomposition of hydrogen peroxide is determined from the mole ratio of the reaction.
Learn more about mole ratio at: brainly.com/question/19099163
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