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3 years ago

Help !!

Physics

1 answer:

777dan777 [17]3 years ago

3 0

<span>One leg is = 12 m, and the other leg is 16 m. </span>

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If the object is released from rest at point p,what is the kinetic energy at the lowest point Q of its swing.

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Answer:

50%

Explanation:

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3 years ago

Actiong-reaction of the bat hits the ball.

nevsk [136]

Answer:

<h3>according to newtons third law ,the force exerted.by the bat hitting the ball will be equal in magnitude . but opposite in direction of the force the ball exerts on the bat</h3>

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2 years ago

A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg

Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

$p_i=mv+0=mv$

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

$p_f=mv'+MV'$

Equating initial and the final momenta we get

$mv=mv'+MV'\\\\m(v-v')=MV'.....i$

Now since the surface is frictionless thus the energy is also conserved thus

$E_i=\frac{1}{2}mv^2$

Similarly the final energy becomes

$E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2$ \

Equating initial and final energies we get

$\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)$

Solving i and ii we get

$v+v'=V'$

Using this in equation i we get

$v'=\frac{v(m-M)}{(M-m)}=-v$

Thus putting v = -v' in equation i we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

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3 years ago

What is the average acceleration of a car that goes from rest to 60 km/h in 8 seconds? Be sure to show all work to support your

wel

The average acceleration can be found by dividing the final speed by the time taken to reach said point so in this case you divide 60 by 8 resulting in 7.5 which will be your answer

5 0

2 years ago

Read 2 more answers

What is the relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum? As t

Elanso [62]

<u>Explanation</u>

The relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum as the bond strength increases the wave number increases.

STRENGTH OF BONDS TRIPLE>DOUBLE>SINGLE

WAVE NUMBER SINGLE>DOUBLE>TRIPLE

wave number for single bond is greatest because it has greatest bond frequency among the three( more the frequency greater is the wave number).

8 0

3 years ago