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son4ous [18]
3 years ago
10

The Pacific Ocean has a durface area of about 116,214,700 km^2 and an average depth of 3940m. Estimate the volume of the Pacific

Ocean in cubic centimeters.​
Physics
1 answer:
Anastaziya [24]3 years ago
4 0

The volume is given by:

V = Ad

V = volume, A = surface area, d = depth

Given values:

A = 116214700km² = 1.162147×10¹⁸cm², d = 3940m = 394000cm

Plug in and solve for V:

V = 1.162147×10¹⁸(394000)

V = 4.57885918×10²³cm³

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Bromine is a liquid at room temperature. The volume of a sample of bromine is measured in a 50 beaker and a 100 ml beaker. How w
Stells [14]

Answer:

The comparisons are;

The height of the bromine in the 50 ml beaker will be twice that of the 100 ml beaker

The measurement of the volume with the 50 ml beaker will be more accurate than the measurement taken with the 100 ml beaker, because the differences in the height of the bromine in the 50 ml beaker is more obvious than the differences measured with the 100 ml beaker.

The actual volume of bromine in both beakers will be equivalent

Explanation:

The properties of a liquid are;

1) The volume of a liquid is relatively fixed at conditions that are suitable for it to remain in the liquid state compared to the volume occupied by a gas

2) A liquid will assume the shape of a container in which it is placed

3) The surface of a liquid in a container is flat due in order that the attractive forces between the molecules of the liquid at the surface and inside the body of the liquid should be in equilibrium

Therefore, given that the volume of the Bromine is measured in 50 ml beaker and a 100 ml beaker, there will be differences in the measured height of the same volume of bromine in each beaker.

5 0
3 years ago
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
labwork [276]

Answer:\tau=1.03\times 10^{-4}\ N-m

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

\tau=NIAB\ \sin\theta

Let us assume that, A=0.0008\ m^2

\theta is the angle between normal and the magnetic field, \theta=90^{\circ}-30^{\circ}=60^{\circ}

Torque is given by :

\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

So, the net torque about the vertical axis is 1.03\times 10^{-4}\ N-m. Hence, this is the required solution.

4 0
3 years ago
WAVES AND SOUND
lawyer [7]

Answer:

i think it is B

Explanation:

6 0
3 years ago
If the strength of a magnetic field at B is three units the strength of the magnetic field at A is ____?
Tema [17]

If the strength of a magnetic field at B is three units the strength of the magnetic field at A, means that point B has three times more turns as compared to point A.

<h3>How strength of the magnetic field should be increased?</h3>

We can increase the strength of the magnetic field by increasing the number of turns which increases the strength of the current flow.

So we can conclude that point B has three times more turns as compared to point A.

Learn more about magnetic field here: brainly.com/question/14411049

#SPJ1

8 0
2 years ago
answer A vertical spring stretches 3.4 cm when a 8-g object is hung from it. The object is replaced with a block of mass 26 g th
victus00 [196]

Answer:

0.695s

Explanation:

From Hooke's law, the restoring force is given has

F = -ky .......1

Where F is the force, y is the spring displacement and k force constant of the spring.

Also recall,

F=mg ............ 2

Where m is the mass of object, g is the acceleration due to gravity.

Equating 1 and 2

Ky = mg

Given that g=9.8m/s2 , y is 3.4cm and g is 8g

K×3.4/100m =8/1000kg × 9.8m/s2

K= ( 0.008kg × 9.8m/s2 ) ÷ 0.034

K= 0.0784÷0.035

K=2.24N/m

Mass ofvthe second object is 25g =0.025kg

Period of oscillation T

T=2π√m/k

T=2×3.142√0.025/2.24

T=6.284√0.0111

T=0.659seconds

8 0
3 years ago
Read 2 more answers
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