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3 years ago

Find the displacement of a hiker if he travels 3.0 m N and then 2.5 m S.

Physics

1 answer:

ankoles [38]3 years ago

4 0

Answer:

.5 m N

Explanation:

Displacement just means distance from starting point, so moving 3 m north then 2.5 m south is the same as if you took 3 steps forward then 2.5 steps backward. The end point is only .5 away from the start point.

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Which of the examples below is an example of convection?

nasty-shy [4]

Basking in the sun :)

3 0

3 years ago

A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

7 0

3 years ago

The U.S. Navy has long proposed the construction of extremely low frequency (ELF waves) communications systems; such waves could

Artyom0805 [142]

Answer:

length of a quarter wavelength antenna for transmitter elf waves are zero

Explanation:

Find the length of a quarter wavelength antenna for transmitter elf waves

Given information

frequency (ELF waves) → 77Hz

Speed of light → 3 $\times$ $10^8$ m/s

$v=\lambda f-------------1$

where

$\lambda\\$ → wavelength of the antenna

f → frequency of the ELF waves

$v$ → speed of light

so rewrite the equation in $\lambda$ from

$\lambda=\dfrac{v}{f}$

Substitute $3\times10^8m/s$ = $v$

Substitute 75Hz = f

$\lambda=\dfrac{3\times10^8m/s}{77Hz}$

$=3.9\times 10^6$ m

since we get this value,but this size of antenna mount on submarine is not possible.

so $\lambda$ is zero

6 0

3 years ago

If you do not receive enough calories, which occurs? 1. Gain weight 2. Too much sugar 3. Impaired metabolic processes 4. Maintai

kipiarov [429]

3 impaired metabolic processes

5 0

3 years ago

In which instrument of the following the water works as a bulb

Montano1993 [528]

Answer:

hydrometer

Explanation:

A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water.

3 0

3 years ago