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2 years ago

A famous physics tale is about a rich man who was found dead. He was

1 answer:

7 0

<h2>Answer: C) He could have thrown the bag of money sideways, creating a horizontal reaction force on himself.</h2>

Explanation:

According to Newton's third law of motion, when two bodies interact between them, appear equal forces and opposite senses in each of them.

To understand it better:

Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude and direction but in the opposite direction on the first.

So, if the rich man had pushed the bag of money horizontally opposite of where he was, he could have saved himself.

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Energy is the energy an object has because it is in motion. *

Mrrafil [7]

The energy an object has due to its motion is called kinetic energy.

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1 year ago

Why can even a small injury to the cornea have a major effect on vision?

Rudik [331]

Your eyes are the most delicate thing on your body. Little things can make you go blind

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3 years ago

Aaron's normal response time to apply the car brakes is 0.7 seconds. Aaron's response time doubles when he is tired. How far wil

Likurg_2 [28]

Aaron's car is moving at speed of 30 m/s

His reaction time is given as 0.7 s

but when he is tired the reaction time is doubled

Now we need to find the distance covered by his car when he is tired during the time when he react to apply brakes

So here since during this time speed is given as constant so we can say that distance covered can be product of speed and time

So here we can use

$d = v*t$

$d = 30 * 1.4$

$d = 42 m$

So the car will move to 42 m during the time when he apply brakes

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3 years ago

Find the force necessary to pull a 6 kg object 3 m/s2

mars1129 [50]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6 × 3

We have the final answer as

Hope this helps you

6 0

2 years ago

What is the fundamental frequency (in Hz) of a 0.632 m long tube, open at both ends, on a day when the speed of sound is 344 m/s

Greeley [361]

Answer:

$f=272.15Hz$

Explanation:

Given data

Length of tube L=0.632 m

Speed of sound v=344 m/s

To find

Fundamental frequency f

Solution

The fundamental frequency of the tube can be given as:

$f=\frac{v}{2L}\\ f=\frac{344m/s}{2(0.632m)}\\ f=272.15Hz$

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3 years ago