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Luba_88 [7]
3 years ago
6

A computer simulation is an example of what?

Physics
1 answer:
Lelechka [254]3 years ago
8 0
<h3>A computer simulation is an example of a <u>Model</u>.</h3>

A model can be a virtual OR physical representation of an object, movement, etc. A model is used to have a visual view of an item.

Hope this helps and please mark brainliest!

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How do uplift and erosion help to form a batholith?
saul85 [17]
<span>the correct answer would be <u>by exposing a large body of igneous rock to the surface

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6 0
3 years ago
Read 2 more answers
A stone is thrown straight up from the roof of an 80 ft building. the height, in feet, of the stone at any time t, in seconds, m
julsineya [31]

Answer:

144 ft

Explanation:

h(t) = -16t² + 64t + 80

The maximum height is at the vertex.  We can find the vertex of a parabola using -b / (2a):

t = -64 / (2×-16)

t = 2

The vertex is at 2 seconds.  The height of the stone at this time is:

h(2) = -16(2)² + 64(2) + 80

h(2) = 144

The maximum height is 144 feet.

8 0
4 years ago
A person of mass m measures their weight with a scale. How does the person’s weight measurement at the equator, WEQ, compare wit
lakkis [162]

Answer:

Weight measurement at poles will be slightly more than at equator.

Explanation:

Firstly earth bulges at equator. This makes the body far from earth center at equator than poles. Secondly, the surface centrifugal forces of earth due to rotation also plays vital role in disturbing the gravity value. The centrifugal forces cancel the effect of gravity more at equator than at poles.These factors combine to create difference of about 0.5% in gravity values at pole and equator.

gravity at pole=9.832 m/s^2

gravity at equator=9.780 m/s^2

5 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 4.05 km/s, while that of the longitudinal waves is 7.695 km/s.
lora16 [44]

Answer:

x = 600 Km

Explanation:

given,

speed of transverse wave = 4.05 Km/s

speed of longitudinal wave = 7.695 Km/s

difference of the time of arrival of wave = 69.9 s

now,

t₂ - t₁ = 69.9 s

let x be the distance

\dfrac{x}{4.05} - \dfrac{x}{7.695} = 69.9

x = \dfrac{69.9\times 4.05 \times 7.695}{7.695-4.05}

x = 597.645 Km

x = 600 Km

distance of recorder from the site is 600 Km approximately.

4 0
4 years ago
Cuales son dispositivos de salida?
Jobisdone [24]

Answer:

el monitor,las impresoras y las memorias portátiles

5 0
3 years ago
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