Question

If 20 ml of gas is subjected to a tempature change from 10 Celsius to 100 Celsius and a pressure change from 1 atm to 10 atm, the expression best representing the new volume is?

Answer 1

Answer:

V₂ = 2.64 mL

Explanation:

Given data:

Initial volume = 20 mL

Initial pressure = 1 atm

Initial temperature = 10°C (10 +273 = 283 K)

Final temperature = 100°C (100+273 = 373 K)

Final volume = ?

Final pressure = 10 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm. 20 mL . 373 K / 283 K. 10 atm

V₂ = 7460 mL.K.atm / 2830 K.atm

V₂ = 2.64 mL