Question

When calcium carbonate is heated, it produces calcium oxide and carbon dioxide. The equation for the reaction is CaCO3(s) CaO(s) CO2(g). How many grams of calcium carbonate (molar mass

Answer 1

When calcium carbonate is heated, it produces calcium oxide and carbon dioxide. The equation for the reaction is CaCO3(s) CaO(s) CO2(g). How many grams of calcium carbonate (molar mass = 100 g/mol) need to decompose to produce 44.5 g of Calcium oxide.

Answer: 79.5 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP, contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to the molecular mass of the substance.

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

According to stoichiometry :

1 mole of CaO is produced by 1 mole of $CaCO_3$

That means 56 g of CaO is produced by 100 g of $CaCO_3$

Thus 44.5  g of CaO is produced by =$\frac{100}{56}\times 44.5=79.5g$ of $CaCO_3$

Thus 79.5 g of $CaCO_3$ need to decompose to produce 44.5 g of Calcium oxide.