When calcium carbonate is heated, it produces calcium oxide and carbon dioxide. The equation for the reaction is CaCO3(s) CaO(s)
1 answer:
When calcium carbonate is heated, it produces calcium oxide and carbon dioxide. The equation for the reaction is CaCO3(s) CaO(s) CO2(g). How many grams of calcium carbonate (molar mass = 100 g/mol) need to decompose to produce 44.5 g of Calcium oxide.
Answer: 79.5 grams
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP, contains avogadro's number of particles and weighs equal to the molecular mass of the substance.
According to stoichiometry :
1 mole of CaO is produced by 1 mole of
That means 56 g of CaO is produced by 100 g of
Thus 44.5 g of CaO is produced by = of
Thus 79.5 g of need to decompose to produce 44.5 g of Calcium oxide.
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Moles of solute for both a and b are the same = 1 mol
<h3>Further explanation</h3>Given
a 500 cm³ of solution, of concentration 2 mol/dm³
b 2 litres of solution, of concentration 0.5 mol/dm³
Required
moles of solute
Solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution
Can be formulated :
a.
V = 500 cm³ = 0.5 L
M = 2 mol/L
n=moles = M x V
n = 2 mol/L x 0.5 L
n = 1 mol
b.
V = 2 L
M = 0.5 mol/L
n=moles = M x V
n = 0.5 mol/L x 2 L
n = 1 mol