Whats the equation to find the total cost ?

Which of these is equal to the value of 9 – (–5)?

DerKrebs [107]

14.

Subtracting a negative number is like adding a positive number. So, you can change 9 - (-5) into 9 + 5, which is much simpler. Then, just add to get 14.

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3 0

3 years ago

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Karl’s math class is playing a number game. Each student is given a number card containing the numbers 1 to 6. The rules of the

Lena [83]

By finding the probability, we can expect that 2 out of the 30 students will win the prize.

<h3>How many of the 30 students will win the prize?</h3>

First, we should get the probability of winning this game.

Here the students select two numbers out of 6, just to make the calculations let's say that these numbers are 1 and 2.

Now, we need to get these two numbers in two balls. The probability of getting the ball with the number 1 out of the 6 balls is:

p = 1/6

The probability of getting the ball with the number 2 out of the remaining 5 balls (because we already got one) is:

q = 1/5

The joint probability is then:

P = 2*(1/6)*(1/5) = 1/15.

Where the factor 2 comes to take in account the permutations, for the case where we first draw the number 2 and then the number 1.

Then the expected number of students that will win is equal to the probability times the total number of students:

(1/15)*30 = 2

So out of the 30 students, we can expect that 2 will win.

If you want to learn more about probability:

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8 0

2 years ago

Solve the system using elimination. x − y = 4 −x − y = 6

kap26 [50]

X= 2 and y=-2 check by multiplying

4 0

3 years ago

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$