Answer:
Explanation:
The fundamental mode of the standing wave in string is expressed as;
fo
F = V/2L where;
V is the speed of the transverse wave
L is the length of the string
Given
V = 40.0m/s
L = 2.00m
F = 40.0/2(2)
F = 40/4
F = 10Hertz
Hence the fundamental mode of the standing wave is 10Hz
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<em>Overtone/harmonics are integral multiples of the fundamental frequency.</em>
Note that 1st overtone is also called second harmonic
Second harmonic
First overtone F1 = 2F
Second overtone/Third harmonics = 3F
First overtone F1 = 2*10
First overtone = 20Hz
3rd harmonic = 3*10
3rd harmonic = 30Hz
Answer:
Pressure = 20 MPa
Explanation:
Given:
Force acting on the shoe is,
Area of shoe on which the force acts is,
Now, first we convert the area into its standard unit of m².
We have the conversion factor as:
1 cm² =
Therefore, the area of shoe in square meters is given as:
Now, pressure on the shoe is given as:
Plug in 100 N for 'F', for 'A' and solve for 'P'. This gives,
Now, we know that,
Therefore, the pressure acting on the shoe is 20 MPa.
1. Frequency is the number of complete waves that pass a point in a second. 2.Wavelength is the distance between two crests or two troughs. 3.Time period <span> is the time it takes for one complete wave to pass a given point. 4. Amplitude is the height of the wave. Hence option 4 is correct. </span>
Answer:
Pinhole cameras rely on the fact that light travels in straight lines – a principle called the rectilinear theory of light. This makes the image appear upside down in the camera. ... When the shutter is opened, light shines through to imprint an image on photographic paper or film placed at the back of the camera
Explanation:
Answer:
(a) F= 6.68*10¹¹⁴ N (-k)
(b) F =( 6.68*10¹¹⁴ i + 7.27*10¹¹⁴ j ) N
Explanation
To find the magnetic force in terms of a fixed amount of charge q that moves at a constant speed v in a uniform magnetic field B we apply the following formula:
F=q* v X B Formula (1 )
q: charge (C)
v: velocity (m/s)
B: magnetic field (T)
vXB : cross product between the velocity vector and the magnetic field vector
Data
q= -1.24 * 10¹¹⁰ C
v= (4.19 * 10⁴ m/s)î + (-3.85 * 10⁴m/s)j
B =(1.40 T)i
B =(1.40 T)k
Problem development
a) vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)i =
= - (-3.85*1.4) k = 5.39* 10⁴ m/s*T (k)
1T= 1 N/ C*m/s
We apply the formula (1)
F= 1.24 * 10¹¹⁰ C* 5.39* 10⁴ m/s* N/ C*m/s (-k)
F= 6.68*10¹¹⁴ N (-k)
a) vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)k =
=( - 5.39* 10⁴i - 5.87* 10⁴j)m/s*T
1T= 1 N/ C*m/s
We apply the formula (1)
F= 1.24 * 10¹¹⁰ C* ( 5.39* 10⁴i + 5.87* 10⁴j) m/s* N/ C*m/s
F =( 6.68*10¹¹⁴ i + 7.27*10¹¹⁴ j ) N