Answer:
hello the diagram related to this question is missing attached below is the missing diagram
Answer :
The magnitude of the electric field = 4KQ / L^2
direction = 45° east to south
Explanation:
The magnitude of the electric field = 4KQ / L^2
direction = 45° east to south
The time that the car take to catch up to truck would be :
1/2 ar^2 = vt
1/2 (3) t^2 = 15t
1.5 t^2 = 15t
t ^2 = 10s
Hope this helps
F=ma
F= 4x1.2
F= 4.8 N
F= 4gsin30 - Friction
Friction= 19.6 - 4.8 N
Friction= 14.8 N
Friction= u x 4gcos30
14.8 / 4gcos30 = u
u= 0.43596...
u= 0.44
coefficient is 0.44
<span>principal quantum number (n) </span>represents the relative overall energy of each orbital
Hope this helps!
