Answer:
α = 1.114 × 10⁻³ (°C)⁻¹
Explanation:
Given that:
Length of rod (L) = 1.5 m,
Diameter (d) = 0.55 cm,
Area (A) = 
Radius (r) = d / 2 = 0.275 cm,
Voltage across the rod (V) = 15.0 V.
At initial temperature (T₀) = 20°C, the current (I₀) = 18.8 A while at a temperature (T) = 92⁰C, the current (I) = 17.4 A
a) The resistance of the rod (R) is given as:

Therefore the resistivity and for the material of the rod at 20 °C (ρ) is:
b) The temperature coefficient of resistivity at 20°C for the material of the rod (α) can be gotten from the equation:
![R_T=R_0[1-\alpha (T-T_0)]\\but,R_T=\frac{V}{I}=\frac{15}{17.4}=0.862\\](https://tex.z-dn.net/?f=R_T%3DR_0%5B1-%5Calpha%20%28T-T_0%29%5D%5C%5Cbut%2CR_T%3D%5Cfrac%7BV%7D%7BI%7D%3D%5Cfrac%7B15%7D%7B17.4%7D%3D0.862%5C%5C)
Rearranging to make α the subject of formula:

Answer:
0.69s
Explanation:
10 cm = 0.1 m
Let t be the time that radial and tangential components of the linear acceleration of a point on the rim be equal in magnitude. At that time we have the angular velocity would be

And so the radial acceleration is

The tangential acceleration is always the same since angular acceleration is constant:

For these 2 quantities to be the same




Answer:
Hope it will help you ^_^
Explanation:
Answer:
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Explanation: