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grigory [225]
3 years ago
5

Give two of your own examples of square roots that are irrational numbers and two rational numbers .

Mathematics
2 answers:
Basile [38]3 years ago
8 0

Answer:

irrational number √3 can't be written as a ratio of two integers numbers.​​

irrational number √5 ​can't be written as a ratio of two integers numbers.

rational number √4 can be written as a ratio of two integer numbers 2/1

rational number √9 can be written as a ratio of two integer numbers​ 3/1

\textit{\textbf{Spymore}}​​

Vikentia [17]3 years ago
6 0

Irrational

\sqrt{2}

\sqrt{3}

Rational:

\sqrt{1}

\sqrt{4}


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7 0
3 years ago
What is f(x) = –4x2 + 24x + 13 written in vertex form? f(x) = –4(x – 6)2 + 23 f(x) = –4(x – 6)2 + 7 f(x) = –4(x – 3)2 + 4 f(x) =
nika2105 [10]
We have that
f(x) = –4x²<span> + 24x + 13
</span>
we know that

The vertex form for a parabola that opens up or down is:

f(x) = a(x - h)^2 + k

in the given equation, <span>a=-4</span><span>, therefore we add zero to the original equation in the form of </span><span>4h</span>²<span>−4h</span>²
f(x) = –4x² + 24x + 4h²−4h² +13
<span>Factor 4 out of the first 3 terms and group them 
</span>f(x) = –4*(x² -6x +h²) +4h² +13
<span>We can find the value of h by setting the middle term equal to -2hx
</span>−2hx=−6x
<span>h=3</span><span> and  </span><span>4h</span>²<span>=<span>36
</span></span>f(x) = –4*(x² -6x +9) +36 +13

we know that the term (x² -6x +9) is equals to------> (x-3)²
so
f(x) = –4*(x-3)² +49

the answer is
f(x) = –4*(x-3)² +49

 

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3 years ago
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solniwko [45]

Answer:

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3 years ago
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HELP THIS IS DUE SOON!<br><br> find the error!
Rudik [331]

Answer:

Step 1

Step-by-step explanation:

they were supposed to multiply 2x by 4 and -1 by 4 but they only multiplied 2x by 4.

3 0
2 years ago
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