All categories

2 years ago

Write an exponential function in the form y=ab^(x) that goes through points (0,4) and (6, 2916)

Mathematics

1 answer:

8_murik_8 [283]2 years ago

7 0

Answer:

y=4(3)^x

Step-by-step explanation:

You might be interested in

Solve. solve this question if you are intelligent

ASHA 777 [7]

Answer:

(a) 0 (b) 1^2

Step-by-step explanation:

photo number 1 is answer for question 2(a)

photo number 2 is answer for question 2(b)

3 0

1 year ago

A quarter back is sacked for a loss of 4 yards. On the next play his team loses 10 yards. Then the team gains 12 yards on the th

KengaRu [80]

Answer:

see below

Step-by-step explanation:

loss of 4 yards

-4

loses 10 yards.

-10

gains 12 yards

+12

The expression for the three plays

-4 +(-10) + 12

The sum is

-2

The team needs to gain 10 yards to make a first down and instead they lost 2 yds

7 0

2 years ago

Look at the table showing prices of different items at a store.

Natalija [7]

notebooks and paperback

7 0

2 years ago

Read 2 more answers

Simplified product ?

mel-nik [20]

Answer:

Last choice is correct.

Step-by-step explanation:

$\left(\sqrt{10x^4}-x\sqrt{5x^2}\right)\left(2\sqrt{15x^4}+\sqrt{3x^3}\right)$

$\left(x^2\sqrt{10}-x\cdot x\sqrt{5}\right)\left(2\cdot x^2\sqrt{15}+x\sqrt{3x}\right)$

$\left(x^2\sqrt{10}-x^2\sqrt{5}\right)\left(2x^2\sqrt{15}+x\sqrt{3x}\right)$

$x^2\sqrt{10}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)-x^2\sqrt{5}\left(2x^2\sqrt{15}+x\sqrt{3x}\right)$

$2x^4\sqrt{150}+x^3\sqrt{30x}-2\sqrt{75}x^4-x^3\sqrt{15x}$

$2x^4\cdot5\sqrt{6}+x^3\sqrt{30x}-2\cdot5\sqrt{3}x^4-x^3\sqrt{15x}$

$10x^4\sqrt{6}+x^3\sqrt{30x}-10\sqrt{3}x^4-x^3\sqrt{15x}$

$10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

Hence final answer is $10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}$

5 0

2 years ago

2hat is the sum of 2x-5y need help asap plz

damaskus [11]

Because these are not like terms, they cannot be combined. The variables are different, that's what makes them not like terms

4 0

3 years ago