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Sphinxa [80]
3 years ago
11

Please awnser these questions on the picture 50 points

Chemistry
2 answers:
harkovskaia [24]3 years ago
7 0
1 - valence electrons
2 - electrons
3 - two electrons
4 - eight electrons
5 - eighteen electrons
6 - nucleus
7 - protons
8 - neutrons
9 - shell or energy level
10- atomic number
11 - element symbol
12 - atomic name
13 - atomic mass
Ivanshal [37]3 years ago
6 0

Answer:

1- valence electrons

2 - electrons

3 - two electrons

4 - eight electrons

5 - eighteen electrons

6 - nucleus

7 - protons

8 - neutrons

9 - shell or energy level

10- atomic number

11 - element symbol

12 - atomic name

13 - atomic mass

Explanation:

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What is the mass of the solute in 250 mL of 0.122 mol/L potassium phosphate?
inysia [295]

Answer:

What is the mass of solute, in grams, in 250.00 mL of a 0.0125 M solution of KMnO4? Moles KMnO4 = M × V = 0.0125 M × 0.250 L = 3.13 × 10-3 mol KMnO4 grams KMnO4 = 3.13 × 10-3 mol KMnO4 × ( 158.03 g KMnO4/1 mol KMnO4) = 0.495 g 4.

8 0
3 years ago
4) What is the mass of 5.20 moles of sodium bicarbonate, NaHCO3? Hint: To solve this problem
inysia [295]
The mass is 437 g NaHCO3 and this is my work shown

8 0
3 years ago
Why does bromine not react with aqueous potassium chloride
rusak2 [61]
Hey there,
That is because, chlorine is more reactive than Bromine. 

**Important note: The lower you go in the periodic table of elements, the less reactive the elements become.

Hope this helps :))

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8 0
3 years ago
What two kinds of properties give a substance its unique identity, and what are some examples of each?
djyliett [7]
Some physical properties would be:
appearance, odor, density, and magnetism.
Some chemical properties would be:
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Hope this helps. (;
5 0
3 years ago
What mass of water will change its temperature by 3.0 0C when 525 J of heat is added to it? The specific heat of water is 4.184
pav-90 [236]

Answer:

Mass of water = 41.8 g

Explanation:

Given data:

Mass of water = ?

Change in temperature = 3.0 °C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = 525 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C  × 3.0°C

525 J = m × 12.552 j/g

m =  525 J/ 12.552 j/g

m = 41.8 g

4 0
3 years ago
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