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Ksenya-84 [330]
3 years ago
9

For the reaction2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (g)ΔH° is -125 kJ/mol and ΔS° is +253 J/K ∙ mol. This reaction is _

___.A. spontaneous only at low temperatureB. spontaneous only at high temperatureC. spontaneous at all temperaturesD. nonspontaneous at all temperaturesE. unable to determine without more information
Chemistry
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

C. spontaneous at all temperatures

Explanation:

The spontaneity of  reaction is determined by the sign of the  gibbs free energy.

A negative sign denotes that the reaction is spontaneous, positive sign means the reaction is not spontaneous.

From the question;

ΔS° = +253 J/K

ΔH° = -125 kJ/mol

ΔG = ΔH°  - TΔS°

From the data given, the condition in which we can obtain a negative value of G, is at any value of T.

For any value of T, G would always be a negative value.

This means the correct option is option C.

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What is the overall equation for this chemical reaction?
ahrayia [7]

Answer:

Mg(s) + 2H⁺ → Mg²⁺(aq) + H₂.

Explanation:

  • To obtain the overall reaction, we sum the two half-reactions and omit the similar species in the reactants and products sides.
  • We have two reactions:

oxidation reaction:

Mg(s) → Mg²⁺(aq) + 2e.

Reduction reaction:

2H⁺ + 2e → H₂.

  • So, we add the two half-reactios and obtain the overall reaction:

<em>Mg(s) + 2H⁺ → Mg²⁺(aq) + H₂.</em>

<em></em>

3 0
4 years ago
What is the main difference in covalent bonds in diatomic chlorine and diatomic oxygen? diatomic means two atoms of the same typ
Aneli [31]
The correct response is C. Chlorine forms 1 covalent bond while Oxygen forms 2 covalent bonds.
3 0
4 years ago
For many purposes we can treat butane (C4H10) as an ideal gas at temperatures above
masha68 [24]

Answer:

A. Yes

B. –176 °C

Explanation:

A. Yes

B. Determination of the new temperature of the gas.

Let the initial pressure be P

From the question given above, the following data were obtained.

Initial pressure (P1) = P

Initial temperature (T1) = 19 °C

Final pressure (P2) = ⅓ P1 = ⅓P = P/3

Final temperature (T2) =?

Next, we shall convert 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 19 °C

Initial temperature (T1) = 19 °C + 273

Initial temperature (T1) = 292 K

Since the volume is constant, we can obtain the new temperature of the gas as illustrated below:

Initial pressure (P1) = P

Initial temperature (T1) = 292 K

Final pressure (P2) = P/3

Final temperature (T2) =?

P1/T1 = P2/T2

P/292 = P/3 /T2

P/292 = P/3T2

Cross multiply

P × 3T2 = 292 × P

Divide both side by P

3T2 = (292 × P)/P

3T2 = 292

Divide both side by 3

T2 = 292/3

T2 = 97.33 ≈ 97 K

Finally, we shall convert 97 K to celcius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 97

T(°C) = 97 – 273

T(°C) = –176 °C

Thus, the new temperature of the gas is –176 °C.

6 0
3 years ago
Why is the molecular formula for a disaccharide not double that of a monosaccharide?
Firlakuza [10]
The reason the molecular formula for a disaccharide is not simply double that of a monosaccharide is because when the covalent bond is formed between the carbons of each sugar, an H of one is removed along with an OH from the other. This resulting loss of an H + OH forms H2O (water), therefore the reaction combining the two sugars covalently is called a "dehydration synthesis."
For example, in combining 2 glucose (C6H12O6) molecules, instead of it being 2 × C6H12O6 = C12H24O12, the dehydration synthesis removes 1 H2O to make room for the C-C covalent bond between the two sugars' carbons. Therefore it is 2 H's and 1 O less than that doubling, or: C12H22O11
3 0
4 years ago
Can someone help pls! I’m very confused on this!!
Klio2033 [76]
1. 160,000
2. 160,00
You just have to multiply the volume and the buffer.
6 0
3 years ago
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