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MArishka [77]
3 years ago
7

Create an element card that has the following information:

Chemistry
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

Atomic number:6

Atomic mass:12.011

Chemical symbol:C

Name of element: Carbon, Carbone (french)

Image is in my explanation

Explanation:

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Determine two complex numbers, (a+bi) and (c+di), where a and d are irrational numbers and b and c are rational number
Dafna11 [192]

Answer:

The two complex numbers are \sqrt2 + 5i \text{ and } 6 + \sqrt5i

Explanation:

We have to form two complex numbers of the form

a + ib\\c + id

such that and d are irrational numbers and b and c are rational numbers.

We know that \sqrt2, \sqrt3 are irrational numbers.

5 and 6 are rational numbers.

We put

a = \sqrt2\\b = 5\\c = 6\\d = \sqrt5\\a+ib = \sqrt2 + 5i\\c + id = 6 + \sqrt5i

Thus, the two complex numbers are: \sqrt2 + 5i \text{ and } 6 + \sqrt5i

7 0
3 years ago
Read 2 more answers
Give 3 example<br>of a<br>solid that sublimes.​
tino4ka555 [31]

Here are a few examples :)

iodine (I2)

naphthalene

aresenic (As)

ferrocene

water (H2O)

carbon dioxide (CO2)

Hope this helps :)

5 0
3 years ago
How many particles are in 3.2 mole of neon gas
Cerrena [4.2K]

There are 1.93 x 10²⁴ particles

<h3>Further explanation</h3>

Given

3.2 moles of Neon gas

Required

Number of particles

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

<em>1 mol = 6.02.10²³ particles </em>

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So the number of particles for 3.2 moles :

N = 3.2 x 6.02.10²³

N = 1.93 x 10²⁴

or

we can describe it using Avogadro's number conversion factor

\tt 3.2~moles\times \dfrac{6.02\times 10^{23}}{1~mole}=1.93\times 10^{24}

7 0
3 years ago
How many moles (of molecules or formula units) are in each sample? 79.34 g cf2cl2?
Alona [7]
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of fluorine = 18.99 grams
molecular mass of chlorine = 35.5 grams
Therefore:
one mole of CF2Cl2 = 12 + 2(18.99) + 2(35.5) = 120.98 grams
Therefore, we can use cross multiplication to find the number of moles in 79.34 grams as follows:
mass = (79.34 x 1) / 120.98 = 0.6558 moles

Now, one mole contains 6.022 x 10^23 molecules, therefore:
number of molecules in 0.65548 moles = 0.6558 x 6.022 x 10^23
                                                              = 3.949 x 10^23 molecules
7 0
3 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
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