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3 years ago

How do i find the answer?

Mathematics

1 answer:

luda_lava [24]3 years ago

4 0

Answer:

jhgfghjk

Step-by-step explanation:

tngbunjregtnmf rejdmnf vfrjelkfnm e3jkwnrmfd

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What are the solution(s) to the quadratic equation 40 - x2 = 0?

Zanzabum

Answer:

$x=\pm2\sqrt{10}$

Step-by-step explanation:

You want to solve ...

$40 -x^2=0\\\\40=x^2\qquad\text{add $x^2$}\\\\\pm\sqrt{40}=x\qquad\text{take the square root}\\\\\boxed{x=\pm2\sqrt{10}}\qquad\text{simplify}$

5 0

3 years ago

Determine whether the inequality is always, sometimes, or never true.

Molodets [167]

Treat this as an ordinary linear equation. Try to isolate x, as some value. Also remember the basic rules of inequalities: If you're dividing, or multiplying, by a negative, you flip the inequality.

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3 years ago

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The scatter plot shows the number of people at a fair based on the outside temperature. How many fewer people would be predicted

frez [133]

Answer

1.-0.08

Step-by-step explanation:

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3 years ago

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Evaluate expression 8s-5t+s2;s=4,t=1

jeka57 [31]

8(4)-5(1)+2(4)
Multiply
32-5+8
Solve from left to right
28+8
36

The answer is 36

4 0

3 years ago

A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ

Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = $2.2\times 7.4=16.28$

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = $2.2\times -6.2=-13.64$

Thus change in moment is: $16.28-(-13.64)=29.92$

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

$\frac{29.92}{0.25}=119.68$

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0

3 years ago