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Reptile [31]
3 years ago
6

A colored solution gives the maximum absorbance value in the spectrophotometer at the wavelength of 533 nm. what are the absorbe

d and perceived colors of this solution?
Chemistry
1 answer:
suter [353]3 years ago
5 0
The absorbed and perceived color of the solution at wavelength 533 nm will be GREEN AND YELLOW.
The spectrophotometer is an analyzing machine that uses the interaction between the radiation from the visible of part of the electromagnetic spectrum and the behavior of chemical species to identify compounds.
When all the wavelength in the visible light is present, we see the color of the light as white but when a wavelength is removed or absorbed, the white color will change to another color. This is the principle on which the spectrophotometer work. Thus, when the wavelength of 533 nm is removed, the color that will be perceive is green and yellow.<span />
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ethanol is a common laboratory solvent and has a density of 0.789 g/mL. what is the mass, in grams, of 151 mL of ethanol
natta225 [31]
<em>V = 151 mL = 151 cm³</em>
<em>d = 0,789 g/mL = 0,789 g/cm³</em>
--------------------------------------

d = m/V
m = d×V
m = 0,789×151
<u>m = 119,139g</u>

3 0
3 years ago
Read 2 more answers
Calculate the average obtained from the following weighings of the same object. Do not forget to include formulas, units, and th
bazaltina [42]

Answer:

10.4376 g

Explanation:

First we <u>calculate the sum of the weighings</u>:

  • 10.4375 g + 10.4381 g + 10.4373 g + 10.4376 g = 41.7505 g

Then we <u>divide the sum by the number of weighings to calculate the average:</u>

  • Number of weighings = 4
  • Average = Sum of weighings / Number of weighings
  • 41.7505 g / 4 = 10.4376 g
6 0
2 years ago
Determine the percent ionization of a 0.225 M solution of benzoic acid. Express your answer using two significant figures.
Assoli18 [71]

Answer:

1.68% is ionized

Explanation:

The Ka of benzoic acid, C₇H₆O₂, is 6.46x10⁻⁵, the equilibrium in water of this acid is:

C₇H₆O₂(aq) + H₂O(l) ⇄ C₇H₅O₂⁻(aq) + H₃O⁺(aq)

Ka = 6.46x10⁻⁵ = [C₇H₅O₂⁻] [H₃O⁺] / [C₇H₆O₂]

<em>Where [] are concentrations in equilibrium</em>

In equilibrium, some 0.225M of the acid will react producing both C₇H₅O₂⁻ and H₃O⁺, the equilibrium concentrations are:

[C₇H₆O₂] = 0.225-X

[C₇H₅O₂⁻] = X

[H₃O⁺] = X

Replacing:

6.46x10⁻⁵ = [X] [X] / [0.225-X]

1.4535x10⁻⁵ - 6.46x10⁻⁵X = X²

1.4535x10⁻⁵ - 6.46x10⁻⁵X - X² = 0

Solving for X:

X = -0.0038. False solution, there is no negative concentrations.

X = 0.00378M. Right solution.

That means percent ionization (100 times Amount of benzoic acid ionized  over the initial concentration of the acid) is:

0.00378M / 0.225M * 100 =

<h3>1.68% is ionized</h3>
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2 years ago
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Which process can separate out the solute from the solvent?
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Evaporation of the solution
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