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Reptile [31]
3 years ago
6

A colored solution gives the maximum absorbance value in the spectrophotometer at the wavelength of 533 nm. what are the absorbe

d and perceived colors of this solution?
Chemistry
1 answer:
suter [353]3 years ago
5 0
The absorbed and perceived color of the solution at wavelength 533 nm will be GREEN AND YELLOW.
The spectrophotometer is an analyzing machine that uses the interaction between the radiation from the visible of part of the electromagnetic spectrum and the behavior of chemical species to identify compounds.
When all the wavelength in the visible light is present, we see the color of the light as white but when a wavelength is removed or absorbed, the white color will change to another color. This is the principle on which the spectrophotometer work. Thus, when the wavelength of 533 nm is removed, the color that will be perceive is green and yellow.<span />
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Na2CO3 + 2HCl ---------&gt; 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
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Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • HCl: 2 moles
  • NaCl: 2 moles
  • CO₂: 1 mole
  • H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

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